1Z0-811 Java Basics and Syntax Practice Question
Which THREE are valid ways to declare and initialize an integer variable in Java? (Choose three.)
⚠ Common exam trap
Oracle often tests the distinction between valid integer literal formats and common invalid ones, such as using underscores incorrectly or assuming any letter is valid in hexadecimal, to catch candidates who overlook Java's strict literal syntax rules.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
int x = 1_000;
Java allows underscores in numeric literals (introduced in Java 7) to improve readability, and `1_000` is a valid integer literal representing 1000. The compiler simply ignores the underscores during parsing.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
int x = 2.0;
Why it's wrong here
Double cannot be assigned to int without cast.
- ✓
int x = 1_000;
Why this is correct
Underscore allowed.
- ✗
int x = 0xG;
Why it's wrong here
G is not hex digit.
- ✓
int x = 03;
Why this is correct
Octal literal for 3.
- ✓
int x = 0;
Why this is correct
Valid.
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