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1Z0-811 Array Initializer Syntax Practice Question

Which of the following correctly uses the shorthand array initializer to declare and initialize an array of strings with the elements "A", "B", and "C"?

⚠ Common exam trap

The trap is that some candidates might think that the 'new' keyword is required, but Java allows the shorthand array initializer directly in a declaration, as shown in Option D.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

String[] arr = {"A", "B", "C"};

Option D correctly uses the shorthand array initializer with curly braces directly in the declaration. Option A uses the full syntax with the 'new' keyword, which is also valid but not the shorthand. Option B is wrong because it uses parentheses. Option C is wrong because it uses square brackets.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
String[] arr = new String[] {"A", "B", "C"};
Why it's wrong here
Correct. This uses anonymous array creation with 'new' to declare and initialize the array in one statement.
✗
String[] arr = ("A", "B", "C");
Why it's wrong here
Incorrect. Array initializers use curly braces, not parentheses.
✗
String[] arr = ["A", "B", "C"];
Why it's wrong here
Incorrect. Array initializers use curly braces, not square brackets.
✓
String[] arr = {"A", "B", "C"};
Why this is correct
Correct. This uses the shorthand array initializer syntax with curly braces.

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1Z0-811 Array Initializer Syntax Practice Question

Why each option matters

Option-by-option breakdown

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