Control Flow and Loops →hardMultiple ChoiceObjective-mapped

1Z0-811 Control Flow and Loops Practice Question

Exhibit

Refer to the exhibit.

int sum = 0;
for (int i = 1; i <= 10; i++) {
    if (i % 3 == 0) {
        break;
    }
    sum += i;
}
System.out.println(sum);

What is the value of sum printed?

int sum = 0;
for (int i = 0; i < 3; i++) {

sum = sum + i;

System.out.println(sum);

⚠ Common exam trap

Oracle often tests the off-by-one error where candidates mistakenly include the final value (i=3) or start counting from 1 instead of 0, leading to incorrect sums like 6 or 1.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

The loop initializes sum to 0 and iterates i from 0 to 2 inclusive. In the first iteration, sum = 0 + 0 = 0; second iteration, sum = 0 + 1 = 1; third iteration, sum = 1 + 2 = 3. After the loop, sum is printed, so the output is 3. Option C is correct.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
6
Why it's wrong here
Would be sum if break at i=4.
✗
0
Why it's wrong here
Not correct.
✓
3
Why this is correct
The value 3 is printed because the code correctly implements an arithmetic operation or a loop that iterates precisely three times. For instance, if a `for` loop is initialised to `i = 0` and its condition is `i < 3`, the loop body will execute for `i = 0, 1, 2`, resulting in three increments to the `sum` variable. This satisfies the constraint of the loop's termination condition accurately determining the final accumulated value.
✗
1
Why it's wrong here
Only first iteration.

Go deeper

1Z0-811 Control Flow and Loops Practice Question

Exhibit

Why each option matters

Option-by-option breakdown

Related to this question