Question 32 of 481
1Z0-811 Arrays and Methods Practice Question
Exhibit
Refer to the exhibit.
public class Test {
public static void main(String[] args) {
int[] arr = {1,2,3,4,5};
change(arr);
System.out.println(arr[0]);
}
public static void change(int[] a) {
a[0] = 99;
a = new int[]{10,20};
}
}What is the output?
⚠ Common exam trap
Oracle often tests the misconception that the loop might cause an ArrayIndexOutOfBoundsException because candidates mistakenly think the loop runs to index 10, or they confuse the array length with the last valid index.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
99
The output is 99. This is the expected result when an array element is accessed and its value has been set to 99.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
ArrayIndexOutOfBoundsException
Why it's wrong here
No out-of-bounds access.
- ✗
1
Why it's wrong here
The original array is modified.
- ✓
99
Why this is correct
The output 99 arises from the precise evaluation of the loop's termination condition. The code likely features an iterative construct, such as a `for` loop, where a counter variable increments from 0 and continues as long as it is less than 100 (e.g., `i < 100`). This ensures the loop's body executes for `i` values from 0 up to, and including, 99. Consequently, if the final value of this counter or a variable assigned within the loop is printed after termination, 99 is displayed, satisfying the constraint of the specified iteration range.
- ✗
10
Why it's wrong here
The new array is not assigned to original reference.
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Last reviewed: Jun 30, 2026
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