Question 1mediummultiple choice
Full question →- A
0 1 2 4
Correctly skips 3 due to continue.
- B
0 1 2 3
Why wrong: Missing 4 and includes 3.
- C
0 1 2 4 5
Why wrong: Loop stops at i<5, so 5 not printed.
- D
0 1 2 3 4
Why wrong: Does not skip 3.
Question 34 of 509
Quick Answer
The answer is 0 1 2 4. This output occurs because the continue statement, paired with a variable increment inside the if block, forces the loop to skip the remainder of the current iteration when i equals 3, jumping directly to the next loop condition check. The key technical concept here is that the continue statement does not automatically advance the loop counter; you must explicitly increment i before the continue, otherwise the loop would become infinite. On the Oracle Java Foundations 1Z0-811 exam, this pattern tests your understanding of loop control flow and the common trap of forgetting to increment before a continue, which leads to an endless loop. A reliable memory tip is "increment before you skip"—always ensure your loop variable is updated before the continue keyword to avoid infinite loops.
1Z0-811 Control Flow and Loops Practice Question
This 1Z0-811 practice question tests your understanding of control flow and loops. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
What is the output of the following code?
int i = 0;
while (i < 5) {
if (i == 3) {i++; continue;
}
System.out.print(i + " "); i++;
}
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
0 1 2 4
The while loop iterates while i < 5. When i equals 3, the if condition triggers, incrementing i to 4 and then using continue to skip the print statement for that iteration. Thus, 3 is never printed, and the loop prints 0, 1, 2, and then 4 before i becomes 5 and the loop ends.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
0 1 2 4
Why this is correct
Correctly skips 3 due to continue.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
0 1 2 3
Why it's wrong here
Missing 4 and includes 3.
- ✗
0 1 2 4 5
Why it's wrong here
Loop stops at i<5, so 5 not printed.
- ✗
0 1 2 3 4
Why it's wrong here
Does not skip 3.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Oracle often tests the interaction between continue and the loop variable increment, where candidates mistakenly think continue skips the increment or that the loop prints the value that triggers the continue.
Detailed technical explanation
How to think about this question
The continue statement in Java transfers control to the loop's condition check, skipping the remainder of the current iteration. In this code, when i == 3, i is incremented to 4 before continue, so the next iteration starts with i = 4, which is less than 5, and prints 4. This pattern is common in filtering loops where certain values must be excluded from processing, such as skipping invalid data in a stream.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
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Control Flow and Loops — study guide chapter
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FAQ
Questions learners often ask
What does this 1Z0-811 question test?
Control Flow and Loops — This question tests Control Flow and Loops — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: 0 1 2 4 — The while loop iterates while i < 5. When i equals 3, the if condition triggers, incrementing i to 4 and then using continue to skip the print statement for that iteration. Thus, 3 is never printed, and the loop prints 0, 1, 2, and then 4 before i becomes 5 and the loop ends.
What should I do if I get this 1Z0-811 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Same concept, more angles
3 more ways this is tested on 1Z0-811
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. What is the output of the code?
medium- A.0 1 2 3 4
- B.1 3 4
- C.0 1 2 3
- ✓ D.0 1 3 4
Why D: The code uses a for loop with an if condition that skips the iteration when the loop variable equals 2 using the continue statement. Therefore, the loop prints 0, 1, 3, and 4, but not 2. Option D correctly lists this output.
Variation 2. A developer writes: for(int i=0; i<10; i++) { if(i%2==0) continue; System.out.print(i); }. What is the output?
hard- A.0123456789
- ✓ B.13579
- C.02468
- D.123456789
Why B: The loop iterates from i=0 to i=9. The `continue` statement skips the rest of the loop body when the condition `i%2==0` is true (i.e., when i is even). Therefore, only odd values of i (1, 3, 5, 7, 9) are printed, producing the output '13579'. Option B is correct.
Variation 3. In a Java method, a developer needs to skip the current iteration and move to the next when a certain condition is met inside a for loop. Which statement should be used?
easy- A.return;
- B.exit;
- ✓ C.continue;
- D.break;
Why C: Option D is correct because continue skips the rest of the loop body for the current iteration. Option A is wrong because return exits the method. Option B is wrong because break exits the loop. Option C is wrong because exit is not a Java keyword.
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Last reviewed: Jun 30, 2026
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