1Z0-811 Object-Oriented Programming Practice Question
Exhibit
Refer to the exhibit.
public class Employee {
private String name;
public Employee(String name) { this.name = name; }
public String getName() { return name; }
}
public class Manager extends Employee {
private int teamSize;
public Manager(String name, int teamSize) {
super(name);
this.teamSize = teamSize;
}
}What is the output of: System.out.println(new Manager("Alice", 5).getName());
⚠ Common exam trap
Oracle often tests whether candidates understand that a subclass constructor can pass arguments to a superclass constructor, and that inherited methods like getName() work correctly without additional overrides, causing some to mistakenly think the code fails or returns null.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Alice
The code creates a new Manager object with the name "Alice" and a level of 5, then calls getName() on it. Assuming Manager extends a class (likely Employee) that has a constructor setting the name field via super(name), getName() returns the stored name "Alice". The code compiles and runs without exception, printing "Alice".
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Runtime exception
Why it's wrong here
No exception.
- ✗
Compilation fails
Why it's wrong here
Code compiles; Employee has a no-arg constructor? No, but Manager calls super(name) explicitly.
- ✓
Alice
Why this is correct
Correct; name is set via super constructor.
- ✗
null
Why it's wrong here
super(name) sets name to Alice.
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