1Z0-811 Arrays and Methods Practice Question
Exhibit
Refer to the exhibit.
public class ArrayReturn {
public static int[] getArray() {
int[] a = {1, 2, 3};
return a;
}
public static void main(String[] args) {
int[] b = getArray();
b[0] = 99;
for (int v : getArray()) {
System.out.print(v + " ");
}
}
}What is the output?
⚠ Common exam trap
Oracle often tests the misconception that modifying the loop variable in a for-each loop changes the array, leading candidates to incorrectly expect the value 99 to appear in the output.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
1 2 3
The code defines a method getArray() that returns a new array containing {1, 2, 3}. Two calls to getArray() each return a separate array, and the loop prints the elements of the first array as "1 2 3 ". Option B is correct because the for-each loop iterates over the array in order and prints each element.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Compilation error
Why it's wrong here
The code compiles and runs without error.
- ✓
1 2 3
Why this is correct
Each call to getArray() creates a new array with values {1,2,3}. The modification of b affects the first array, but the second call returns a separate array, so the output is 1 2 3.
- ✗
1 2 3 99
Why it's wrong here
No extra numbers are printed; the for-each iterates over the three elements returned by getArray().
- ✗
99 2 3
Why it's wrong here
This would happen if the second call returned the same array object, but it does not.
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