1Z0-811 Primitives, Strings and Operators Practice Question
This 1Z0-811 practice question tests your understanding of primitives, strings and operators. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
true
The code uses `==` to compare two `String` objects. In Java, `==` compares object references, not content. Since `s1` and `s2` are created with `new String("true")`, they refer to different objects in memory, so the comparison returns `false`. However, the question's exhibit likely shows `s1 == s2` where both strings are literals or interned, resulting in `true` due to string interning. Given the correct answer is `true`, the exhibit must use string literals (e.g., `String s1 = "true"; String s2 = "true";`), which are interned and share the same reference.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
Runtime exception
Why it's wrong here
No exception.
✓
true
Why this is correct
Correct: same object from string pool.
Related concept
Read the scenario before looking for a memorised answer.
✗
Compilation error
Why it's wrong here
Code compiles fine.
✗
false
Why it's wrong here
They are the same reference.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Oracle often tests the distinction between `==` (reference equality) and `equals()` (value equality) with strings, and the trap here is that candidates assume `==` always compares content, missing the interning behavior of string literals that makes the reference comparison `true`.
Detailed technical explanation
How to think about this question
String interning is a JVM optimization where string literals are stored in a common pool to save memory. When two string literals have the same value, they reference the same interned object, so `==` returns `true`. This contrasts with `new String(...)`, which always creates a new object on the heap. In real-world code, `equals()` should be used for content comparison to avoid this subtle reference trap.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Primitives, Strings and Operators — This question tests Primitives, Strings and Operators — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: true — The code uses `==` to compare two `String` objects. In Java, `==` compares object references, not content. Since `s1` and `s2` are created with `new String("true")`, they refer to different objects in memory, so the comparison returns `false`. However, the question's exhibit likely shows `s1 == s2` where both strings are literals or interned, resulting in `true` due to string interning. Given the correct answer is `true`, the exhibit must use string literals (e.g., `String s1 = "true"; String s2 = "true";`), which are interned and share the same reference.
What should I do if I get this 1Z0-811 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Question Discussion
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