Question 1hardmultiple choice
Full question →- A
false
Why wrong: Incorrect.
- B
Compilation fails
Why wrong: Incorrect.
- C
None of the above
Why wrong: Incorrect.
- D
true
Correct due to operator precedence.
Question 3 of 509
Quick Answer
The answer is true. This is correct because in Java, logical operator precedence dictates that the AND operator (&&) is evaluated before the OR operator (||), so the expression `a || b && c` is interpreted as `a || (b && c)`. With `a` false, `b` true, and `c` true, the inner `b && c` yields true, and then `false || true` evaluates to true. On the Oracle Java Foundations 1Z0-811 exam, this concept tests your understanding of how Java groups logical conditions without explicit parentheses, a common source of errors where test-takers mistakenly evaluate left-to-right. A frequent trap is assuming OR has equal or higher precedence, leading to an incorrect false result. To remember the hierarchy, think of AND as multiplication and OR as addition in Boolean algebra—just as multiplication binds tighter than addition, so does && bind tighter than ||.
1Z0-811 Primitives, Strings and Operators Practice Question
This 1Z0-811 practice question tests your understanding of primitives, strings and operators. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Given: boolean a = false; boolean b = true; boolean c = true; System.out.println(a || b && c); What is the output?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
true
In Java, the logical AND operator (&&) has higher precedence than the logical OR operator (||). Therefore, the expression `a || b && c` is evaluated as `a || (b && c)`. Given `a = false`, `b = true`, and `c = true`, `b && c` evaluates to `true`, and then `false || true` evaluates to `true`. Thus, the output is `true`, making option D correct.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
false
Why it's wrong here
Incorrect.
- ✗
Compilation fails
Why it's wrong here
Incorrect.
- ✗
None of the above
Why it's wrong here
Incorrect.
- ✓
true
Why this is correct
Correct due to operator precedence.
Related concept
Read the scenario before looking for a memorised answer.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often evaluate the expression left-to-right without considering operator precedence, mistakenly thinking `a || b` is evaluated first (which would be `true`) and then `&& c` would produce `true && true` = `true`, but the actual precedence changes the grouping, though in this specific case both orders yield `true`; however, the trap is to test whether you know the precedence rule, not just the outcome.
Detailed technical explanation
How to think about this question
Operator precedence in Java follows a strict hierarchy: logical AND (`&&`) has higher precedence (rank 11) than logical OR (`||`, rank 12), meaning `&&` is evaluated first. This is analogous to arithmetic where multiplication precedes addition. In real-world code, relying on precedence can lead to subtle bugs; it is best practice to use parentheses to make the intended order explicit, e.g., `a || (b && c)`, improving readability and reducing errors.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
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Primitives, Strings and Operators — study guide chapter
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FAQ
Questions learners often ask
What does this 1Z0-811 question test?
Primitives, Strings and Operators — This question tests Primitives, Strings and Operators — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: true — In Java, the logical AND operator (&&) has higher precedence than the logical OR operator (||). Therefore, the expression `a || b && c` is evaluated as `a || (b && c)`. Given `a = false`, `b = true`, and `c = true`, `b && c` evaluates to `true`, and then `false || true` evaluates to `true`. Thus, the output is `true`, making option D correct.
What should I do if I get this 1Z0-811 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Same concept, more angles
2 more ways this is tested on 1Z0-811
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. A developer writes: boolean b = !true && false; What is the value of b?
easy- A.Compilation error: invalid operator.
- ✓ B.false
- C.NullPointerException
- D.true
Why B: The expression `!true && false` is evaluated as `(!true) && false`, which is `false && false`. The logical AND (`&&`) operator returns `true` only if both operands are `true`; otherwise, it returns `false`. Therefore, `b` is assigned `false`. Option B is correct.
Variation 2. Given boolean a = true, b = false, c = true; What is the result of (a || b) && (b || c)?
hard- A.Short-circuit evaluation prevents evaluation
- ✓ B.true
- C.Compilation error
- D.false
Why B: a||b = true, b||c = true, true && true = true.
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Last reviewed: Jun 11, 2026
This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.
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