Quick Answer
The correct answer is dynamic binding. This is because dynamic binding, also known as runtime polymorphism, resolves which version of an overridden method to execute based on the actual object type at runtime, not the reference type. When an Animal reference holds a Dog object, the JVM checks the object’s actual class during execution and calls Dog’s makeSound() version, which is exactly what the scenario describes. On the Oracle Java Foundations 1Z0-811 exam, this concept tests your understanding of polymorphism and method dispatch—a common trap is confusing it with static binding (compile-time) or overloading. Remember that dynamic binding is all about “what the object really is,” not what the reference says. A helpful memory tip: “Dynamic means decision at runtime; static means locked in at compile time.”
This 1Z0-811 practice question tests your understanding of object-oriented programming. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A class 'Animal' has a method 'makeSound()'. Subclasses 'Dog' and 'Cat' override it. When calling makeSound() on an Animal reference that actually holds a Dog object, the Dog's version is executed. This is an example of:
Static binding
Why wrong: Static binding occurs for static, private, and final methods at compile time.
Encapsulation
Why wrong: Encapsulation is about data hiding, not method resolution.
Dynamic binding
Method call is determined at runtime based on the object's class.
Method overloading
Why wrong: Overloading is based on method parameters, not inheritance.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
Dynamic binding
Option A is correct because dynamic binding (runtime polymorphism) resolves method calls based on actual object type. Option B is wrong because static binding happens at compile-time. Option C is wrong because overloading is compile-time. Option D is wrong because encapsulation does not relate to method dispatch.
Key principle: NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
Static binding
Why it's wrong here
Static binding occurs for static, private, and final methods at compile time.
Encapsulation
Why it's wrong here
Encapsulation is about data hiding, not method resolution.
Dynamic binding
Why this is correct
Method call is determined at runtime based on the object's class.
Related concept
Static NAT maps one inside address to one outside address.
Method overloading
Why it's wrong here
Overloading is based on method parameters, not inheritance.
Common exam traps
NAT is not only about the public address. The inside/outside interface roles and the ACL or rule that matches traffic are just as important.
Detailed technical explanation
NAT questions usually test address translation, overload/PAT behaviour, static mappings and whether the right traffic is being translated. Read the interface direction and address terms carefully.
Key takeaway
NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.
Real-world example
A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.
What to study next
Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related 1Z0-811 NAT questions on configuration and troubleshooting.
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FAQ
Object-Oriented Programming — This question tests Object-Oriented Programming — Static NAT maps one inside address to one outside address..
The correct answer is: Dynamic binding — Option A is correct because dynamic binding (runtime polymorphism) resolves method calls based on actual object type. Option B is wrong because static binding happens at compile-time. Option C is wrong because overloading is compile-time. Option D is wrong because encapsulation does not relate to method dispatch.
Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related 1Z0-811 NAT questions on configuration and troubleshooting.
Static NAT maps one inside address to one outside address.
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Same concept, more angles
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. A developer writes a class 'Animal' with a method 'sound()'. The 'Cat' subclass overrides 'sound()'. If an Animal reference points to a Cat object, which method is called when sound() is invoked?
easyWhy B: Polymorphism ensures that the overridden method in the actual object's class is called at runtime, even if the reference is of the superclass type.
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Last reviewed: Jun 23, 2026
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