Question 208 of 481
1Z0-811 Arrays and Methods Practice Question
Consider a method that takes an int array and modifies it: public static void doubleArray(int[] arr) { for (int i = 0; i < arr.length; i++) { arr[i] *= 2; } }. What is the output of: int[] nums = {1, 2, 3}; doubleArray(nums); System.out.println(nums[1]);
⚠ Common exam trap
It's easy for candidates to confuse pass-by-value for object references with pass-by-value for primitives, incorrectly assuming the array is copied and the original remains unchanged, leading them to pick the original value (option C).
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
4
The method `doubleArray` multiplies each element of the array by 2. The array `nums` is passed by reference, so modifications inside the method affect the original array. After execution, `nums[1]` (originally 2) becomes 4, which is printed.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
4
Why this is correct
The method doubles each element, so 2 becomes 4.
- ✗
8
Why it's wrong here
Would be 8 if squared, but it's multiplied by 2.
- ✗
2
Why it's wrong here
This is the original value before doubling.
- ✗
3
Why it's wrong here
Not the result of doubling.
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Last reviewed: Jun 25, 2026
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