Question 218 of 509
Arrays and MethodseasyMultiple ChoiceObjective-mapped

Quick Answer

The correct output is 2. This occurs because the break statement in the loop array Java code immediately terminates the entire for loop when the condition `arr[i] == 2` is met at index 1, preventing any further iterations. The counter `count` increments only for indices 0 and 1 before the loop exits, so it reaches 2 instead of 3. On the Oracle Java Foundations 1Z0-811 exam, this tests your understanding of how break alters loop iteration flow within an array traversal—a common trap is assuming the loop completes all elements or that break only skips the current iteration. Remember that break acts like an emergency stop: once triggered, the loop ends right there, no matter how many array elements remain. A helpful memory tip: "Break bails the loop out immediately, no more turns."

1Z0-811 Arrays and Methods Practice Question

This 1Z0-811 practice question tests your understanding of arrays and methods. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

Exhibit

public class Example {
    public static void main(String[] args) {
        int[] nums = {1, 2, 3};
        int[] result = process(nums);
        System.out.println(result[0]);
    }
    public static int[] process(int[] input) {
        int[] output = new int[input.length];
        for (int i = 0; i < input.length; i++) {
            output[i] = input[i] * 2;
        }
        return output;
    }
}

Refer to the exhibit. What is the output?

Question 1easymultiple choice
Full question →

Exhibit

public class Example {
    public static void main(String[] args) {
        int[] nums = {1, 2, 3};
        int[] result = process(nums);
        System.out.println(result[0]);
    }
    public static int[] process(int[] input) {
        int[] output = new int[input.length];
        for (int i = 0; i < input.length; i++) {
            output[i] = input[i] * 2;
        }
        return output;
    }
}

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

2

The code initializes an array `arr` with values {1, 2, 3}. The for loop iterates over the array, and the `if` condition checks if the current element equals 2. When `arr[1]` (value 2) is encountered, the `break` statement exits the loop immediately. The loop executes only twice (for indices 0 and 1), so the counter `count` is incremented twice, resulting in output 2.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • 3

    Why it's wrong here

    This is the third element of original array.

  • 2

    Why this is correct

    result[0] = input[0]*2 = 1*2 = 2.

    Related concept

    Read the scenario before looking for a memorised answer.

  • 1

    Why it's wrong here

    This is the original value, not doubled.

  • 0

    Why it's wrong here

    No element is 0.

Common exam traps

Common exam trap: answer the scenario, not the keyword

Oracle often tests the interaction between `break` and loop counters, where candidates mistakenly count all array elements or forget that `break` exits immediately without completing the remaining iterations.

Detailed technical explanation

How to think about this question

The `break` statement in Java immediately terminates the innermost enclosing loop (for, while, or do-while), transferring control to the statement following the loop. In this case, the loop variable `i` goes from 0 to 2, but when `i == 1` and `arr[i] == 2`, the `break` stops further iterations, so `arr[2]` (value 3) is never processed. This behavior is defined in JLS §14.15 and is commonly used to exit loops early when a condition is met, such as searching for a specific element in an array.

KKey Concepts to Remember

  • Read the scenario before looking for a memorised answer.
  • Find the constraint that changes the correct option.
  • Eliminate answers that are true in general but not in this case.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this 1Z0-811 question test?

Arrays and Methods — This question tests Arrays and Methods — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: 2 — The code initializes an array `arr` with values {1, 2, 3}. The for loop iterates over the array, and the `if` condition checks if the current element equals 2. When `arr[1]` (value 2) is encountered, the `break` statement exits the loop immediately. The loop executes only twice (for indices 0 and 1), so the counter `count` is incremented twice, resulting in output 2.

What should I do if I get this 1Z0-811 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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Last reviewed: Jun 30, 2026

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This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.