The answer is a `for` loop with an `if` statement and `break` inside the body. This is correct because the `break` keyword immediately terminates the loop’s execution when the specified condition—`sum > 100`—is met, allowing you to break out of for loop when condition met without processing any remaining array elements. On the Oracle Java Foundations 1Z0-811 exam, this pattern tests your understanding of loop control flow and the difference between `break` (exits the loop entirely) and `continue` (skips only the current iteration). A common trap is using `return` instead of `break`, which would exit the entire method rather than just the loop. Remember: `break` is your emergency exit for a loop, not for the whole method. Memory tip: think of `break` as a “bail-out” button—once the sum crosses 100, you hit it and walk away.
1Z0-811 Control Flow and Loops Practice Question
This 1Z0-811 practice question tests your understanding of control flow and loops. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A developer writes a loop to iterate over an array of integers. The loop must sum all elements and stop early if the sum exceeds 100. Which control flow construct should be used?
Option B is correct because it uses a for loop with an index variable to iterate over the array, and includes an if statement with a break to exit the loop early when the sum exceeds 100. This ensures all elements are summed until the condition is met, and the loop stops immediately, preventing unnecessary iterations.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
Read the scenario before looking for a memorised answer.
✗
do { sum += arr[i]; i++; } while(i<arr.length && sum <= 100);
Why it's wrong here
Executes at least once unconditionally, may sum before checking.
✗
for(int val : arr) { sum += val; if(sum > 100) break; }
Why it's wrong here
For-each loop cannot modify index; break works but style is unusual.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Oracle often tests the distinction between loop constructs and the correct use of break; the trap here is that candidates may choose the enhanced for loop (Option D) thinking it is simpler, but they overlook that it does not provide an index for array access, or they may incorrectly assume that the do-while loop (Option C) will stop correctly when the sum exceeds 100, when in fact it checks the condition after the body, leading to one extra iteration.
Detailed technical explanation
How to think about this question
The break statement in Java is used to exit a loop prematurely, and it works with for, while, and do-while loops. In the context of array iteration, using an indexed for loop (Option B) gives explicit control over the loop variable, allowing precise management of the sum condition. The enhanced for loop (for-each) is designed for iterating over collections or arrays without index access, but it does not support break in all contexts; in Java, break is allowed in for-each loops over arrays, but the lack of index makes it less suitable when early exit is needed based on a cumulative condition.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Control Flow and Loops — This question tests Control Flow and Loops — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: for(int i=0; i<arr.length; i++) { sum += arr[i]; if(sum > 100) break; } — Option B is correct because it uses a for loop with an index variable to iterate over the array, and includes an if statement with a break to exit the loop early when the sum exceeds 100. This ensures all elements are summed until the condition is met, and the loop stops immediately, preventing unnecessary iterations.
What should I do if I get this 1Z0-811 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. A developer writes a loop that iterates over an array of integers. The loop should stop when it encounters a negative number. Which control flow construct best achieves this?
easy
A.do-while loop
✓ B.for loop with break inside if condition
C.enhanced for loop with return
D.while loop with continue
Why B: Option A is correct because break exits the loop when condition met. Option B is wrong because continue skips to next iteration, doesn't stop loop. Option C is wrong because do-while executes at least once but doesn't provide early exit without additional logic. Option D is wrong because return exits the method, which may not be desired.
Share a tip, memory trick, or ask about the reasoning behind this question. Do not post real exam questions, leaked content, braindumps, or copyrighted exam material. Comments are moderated and may be removed without notice.
This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.
Question Discussion
Share a tip, memory trick, or ask about the reasoning behind this question. Do not post real exam questions, leaked content, braindumps, or copyrighted exam material. Comments are moderated and may be removed without notice.
Sign in to join the discussion.