The answer is a missing break statement after case 'B'. This is the most likely cause because of switch statement fall-through behavior in Java: when a case matches, execution continues into the next case block unless a break explicitly stops it. Since case 'B' lacks a break, after executing its own code, the program falls through to case 'A' (or the next case in sequence), printing 'A' even though the input was 'B'. On the Oracle Java Foundations 1Z0-811 exam, this classic fall-through trap tests your understanding of control flow and is a frequent distractor—many candidates assume each case automatically exits. A common memory tip: think of a waterfall—once you start falling through, you keep going until you hit a break rock. Always check that every case ends with break unless you intentionally want fall-through.
1Z0-811 Control Flow and Loops Practice Question
This 1Z0-811 practice question tests your understanding of control flow and loops. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A programmer writes a switch statement to handle different cases. The code compiles and runs, but the output is unexpected: 'A' prints when the input is 'B'. Which is the most likely cause?
Clue words in this question
Noticing these words before you look at the options changes how you read each choice.
Clue: "most likely"
Why it matters: Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
A break statement is missing after the case 'B'.
In a switch statement, when a case matches, execution continues sequentially through subsequent cases (fall-through) unless a break statement is encountered. If case 'B' lacks a break, after executing its code, the program falls through to the code for case 'A' (or the next case), printing 'A' even though the input was 'B'. This is the classic fall-through behavior in Java.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✓
A break statement is missing after the case 'B'.
Why this is correct
Fall-through from case 'B' to case 'A' occurs without break.
Clue confirmation
The clue word "most likely" in the question point toward this answer.
Related concept
Read the scenario before looking for a memorised answer.
✗
The switch variable type is char but should be String.
Why it's wrong here
Char is valid for switch; type mismatch would cause compile error, not fall-through.
✗
The switch statement is missing a default case.
Why it's wrong here
Missing default does not cause fall-through.
✗
The default case is executed instead of the matched case.
Why it's wrong here
Default runs only when no match, but output shows a different matched case.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Oracle often tests the fall-through behavior of switch statements, where candidates mistakenly assume each case automatically exits after its code, overlooking the need for an explicit break statement.
Trap categories for this question
Command / output trap
Default runs only when no match, but output shows a different matched case.
Detailed technical explanation
How to think about this question
Java's switch statement uses fall-through semantics by design, meaning each case block must explicitly end with a break (or return, throw, etc.) to prevent execution from continuing into the next case. This behavior originates from C and can be exploited intentionally for shared code blocks, but it is a common source of bugs. In Java 14+, switch expressions with arrow syntax (->) eliminate fall-through by default, but traditional switch statements still require explicit breaks.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Control Flow and Loops — This question tests Control Flow and Loops — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: A break statement is missing after the case 'B'. — In a switch statement, when a case matches, execution continues sequentially through subsequent cases (fall-through) unless a break statement is encountered. If case 'B' lacks a break, after executing its code, the program falls through to the code for case 'A' (or the next case), printing 'A' even though the input was 'B'. This is the classic fall-through behavior in Java.
What should I do if I get this 1Z0-811 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Are there clue words in this question I should notice?
Yes — watch for: "most likely". Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. A developer writes a switch statement that checks the day of the week. The code uses fall-through to handle weekdays. What happens if a case does not end with a break?
easy
A.The default case is executed
B.Compilation error
C.Runtime exception is thrown
✓ D.Execution continues to the next case
Why D: Option A is correct. In a traditional switch, without break, execution continues into the next case (fall-through). Option B is wrong because compile error occurs only if there is syntax issue. Option C is wrong because no runtime exception. Option D is wrong because it does not skip.
Last reviewed: Jun 30, 2026
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