Java Basics and Syntax →easyMultiple ChoiceObjective-mapped

1Z0-811 Java Basics and Syntax Practice Question

A package named com.example.util is declared in a file. Where should the file be placed in the directory structure?

⚠ Common exam trap

A common mix-up: candidates confuse the package name with a file name or think the directory structure can be flattened, leading them to pick options that treat the package as a single folder or as a file extension.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

com/example/util/

Java requires that the directory structure of a package matches the package declaration. A package named `com.example.util` must be stored in a directory hierarchy `com/example/util/` so that the Java compiler and runtime can locate the class files based on the fully qualified name. This ensures that the file is accessible via the classpath or module path.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
com.example.util/
Why it's wrong here
Dots are not directory separators on file system.
✗
util/
Why it's wrong here
Missing com/example directories.
✓
com/example/util/
Why this is correct
Directory path matching package hierarchy.
✗
com/example/util.java
Why it's wrong here
This is a file path, not directory.

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1Z0-811 Java Basics and Syntax Practice Question

Why each option matters

Option-by-option breakdown

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