1Z0-811 Object-Oriented Programming Practice Question
A Java class named 'Helper' is defined in package 'utils'. Another class in a different package tries to access a public method of Helper but receives a compilation error. The Helper class is declared as 'class Helper' (without public modifier). What is the likely issue?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The class has package-private access
The Helper class is declared with default (package-private) access because no access modifier is specified. Therefore, it is only accessible within the utils package. A class in a different package cannot access it, even if it tries to call a public method of that class, because the class itself is not accessible. The method's access modifier is irrelevant if the class is not accessible. Option A is incorrect because final does not affect access. Option B is incorrect because static is unrelated to access across packages. Option C is incorrect because abstract does not restrict access.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The method is declared as final
Why it's wrong here
Final prevents overriding, not access from other packages.
- ✗
The method is not static
Why it's wrong here
Static is unrelated to access control; the issue is class visibility.
- ✗
The class is abstract
Why it's wrong here
Abstract classes can still be public; abstract does not restrict access.
- ✓
The class has package-private access
Why this is correct
Default access (no modifier) makes the class accessible only within its package.
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