1Z0-811 Primitives, Strings and Operators Practice Question
A developer writes the following code: String s1 = "Hello"; String s2 = "Hello"; System.out.println(s1 == s2); What is the output?
⚠ Common exam trap
Many exam-takers confuse reference equality (==) with value equality (.equals()), assuming == always returns false for distinct string variables, without considering string interning of literals.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
true
String literals in Java are interned, meaning both s1 and s2 refer to the same String object in the string constant pool. The == operator compares object references, not content, so since both variables point to the same interned string, the comparison yields true.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Compilation fails
Why it's wrong here
The code compiles fine.
- ✗
false
Why it's wrong here
== compares references, but both are the same object due to interning.
- ✓
true
Why this is correct
Both references point to the same interned string.
- ✗
Hello
Why it's wrong here
This is not the output; the output is a boolean.
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