Quick Answer
The answer is 66. In Java, when a char is involved in an arithmetic operation with an int, char to int arithmetic promotion automatically converts the char to its Unicode or ASCII numeric value before the calculation. The character 'A' has the ASCII value 65, so the expression c + 1 evaluates to 66, and the result is assigned to the int variable i, which prints as 66. On the Oracle Java Foundations 1Z0-811 exam, this concept tests your understanding of binary numeric promotion, a common topic in questions about mixed-type arithmetic. A frequent trap is forgetting that char is an unsigned 16-bit integer type, not a string, so it participates directly in math. To remember, think: 'A' is 65, so 'A' + 1 is always 66—just add the numeric value.
This 1Z0-811 practice question tests your understanding of primitives, strings and operators. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A developer writes: char c = 'A'; int i = c + 1; System.out.println(i); What is the output?
66
'A' is 65, plus 1 equals 66.
B
Why wrong: Output is int, not char.
Compilation error: cannot add char and int.
Why wrong: Implicit promotion allowed.
'A1'
Why wrong: String concatenation not used.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
66
In Java, when a `char` is involved in arithmetic with an `int`, the `char` is promoted to its Unicode/ASCII numeric value. 'A' has the ASCII value 65, so `c + 1` becomes 66. The result is an `int`, and `System.out.println(i)` prints the integer 66.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
66
Why this is correct
'A' is 65, plus 1 equals 66.
Related concept
Read the scenario before looking for a memorised answer.
B
Why it's wrong here
Output is int, not char.
Compilation error: cannot add char and int.
Why it's wrong here
Implicit promotion allowed.
'A1'
Why it's wrong here
String concatenation not used.
Common exam traps
Oracle often tests the misconception that `char` and `int` cannot be added, or that the result remains a `char` and would print as a character, causing candidates to choose 'B' instead of the numeric value.
Trap categories for this question
Command / output trap
Output is int, not char.
Detailed technical explanation
Under the hood, Java applies binary numeric promotion to the operands: the `char` is widened to an `int` (since `int` is wider than `char`), and the addition yields an `int`. This is defined in JLS §5.6.2. A real-world scenario is when you need to shift a character by a certain offset (e.g., Caesar cipher), where the arithmetic result must be cast back to `char` if you want a character output.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Primitives, Strings and Operators — This question tests Primitives, Strings and Operators — Read the scenario before looking for a memorised answer..
The correct answer is: 66 — In Java, when a `char` is involved in arithmetic with an `int`, the `char` is promoted to its Unicode/ASCII numeric value. 'A' has the ASCII value 65, so `c + 1` becomes 66. The result is an `int`, and `System.out.println(i)` prints the integer 66.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 30, 2026
This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.
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