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Java Basics and SyntaxhardMultiple ChoiceObjective-mapped

1Z0-811 Java Basics and Syntax Practice Question

A developer uses a switch statement with a String variable. Which is true about this usage?

⚠ Common exam trap

Oracle often tests the Java version where String support was introduced (Java 7), and the trap here is that candidates who learned Java before 7 or who confuse switch with older limitations may incorrectly think Strings are not allowed or that only primitives work.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

It works with strings starting from Java 7

Starting from Java 7 (JSR 334), the switch statement supports String objects in addition to primitive types and enums. The compiler uses the `hashCode()` and `equals()` methods of the String class to evaluate the switch expression against case labels, making it a valid and efficient way to branch on string values.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • It works only with primitive types

    Why it's wrong here

    Strings are allowed since Java 7, not only primitives.

  • It causes a compilation error because strings are not supported

    Why it's wrong here

    Strings are supported in switch from Java 7 onward.

  • It works with strings starting from Java 7

    Why this is correct

    Switch on strings is valid since Java 7.

  • It requires a default case

    Why it's wrong here

    Default case is optional.

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Last reviewed: Jun 30, 2026

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This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.