1Z0-811 Exception Handling and Development Tools Practice Question
Network Topology
A developer tries to compile a modular Java application using the command shown in the exhibit. The compilation fails with the error shown. What is the most likely cause?
⚠ Common exam trap
Oracle often tests the distinction between module path and module source path, trapping candidates who confuse `-d` (output directory) with source path or who think import syntax is the issue when the real problem is a missing module source location.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The `--module-source-path` does not include the location of the utility module.
The error indicates that the compiler cannot find the utility module referenced in the `requires` directive. The `--module-source-path` option must list all directories containing module source code. Since the utility module's source is not included in the specified path, the compilation fails. Option D correctly identifies this missing path as the cause.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The `-d out` flag is incorrectly specified; it should point to the source directory.
Why it's wrong here
`-d` sets the destination for class files; it does not affect module resolution.
- ✗
The `-m` option should be `--module` instead.
Why it's wrong here
`-m` is a valid shorthand for `--module` in javac.
- ✗
The import statement should use the fully qualified class name instead of importing.
Why it's wrong here
Imports are fine; the core issue is that the class is not found on the module path.
- ✓
The `--module-source-path` does not include the location of the utility module.
Why this is correct
The module source path must point to the directory that contains all module source directories; if missing, dependent modules cannot be resolved.
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