Question 388 of 1,639

Mitigate threats using Microsoft Sentinel →hardMultiple ChoiceObjective-mapped

SC-200 Mitigate threats using Microsoft Sentinel Practice Question

This SC-200 practice question tests your understanding of mitigate threats using microsoft sentinel. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

A threat hunter in Microsoft Sentinel writes a KQL query in the Logs blade to find possible data exfiltration. The query uses the CommonSecurityLog table to look for large outbound file transfers from a specific IP address. The analyst wants to include only events where the total bytes sent in a 5-minute window exceed 100 MB. Which KQL operator combination would best achieve this?

Clue words in this question

Noticing these words before you look at the options changes how you read each choice.

Clue: "best"
Why it matters: Signals that multiple options may be partially correct. Choose the option that most directly solves the exact problem described, not the one that sounds most complete.

Question 1hardmultiple choice

Read the full NAT/PAT explanation →

A
CommonSecurityLog | where SourceIp == '10.0.0.1' | summarize totalBytes = sum(BytesSent) by bin(TimeGenerated, 5m) | where totalBytes > 100000000
Correct. This groups events by 5-minute windows, sums bytes sent per window, and filters those windows exceeding 100 MB (100000000 bytes).
B
CommonSecurityLog | where SourceIp == '10.0.0.1' | extend bin = bin(TimeGenerated, 5m) | where BytesSent > 100000000
Why wrong: This filters individual events where a single BytesSent exceeds 100 MB, not the aggregate over a window. It does not sum multiple events.
C
CommonSecurityLog | where SourceIp == '10.0.0.1' | summarize make_list(BytesSent) by TimeGenerated | where array_length(make_list) > 100000000
Why wrong: make_list creates a list of values, not a sum. The where condition on array length is meaningless for byte total.
D
CommonSecurityLog | where SourceIp == '10.0.0.1' | project BytesSent, TimeGenerated | summarize sum(BytesSent) by bin(TimeGenerated, 5m) | where sum_BytesSent > 100000000
Why wrong: This is almost correct except the last where clause references 'sum_BytesSent' instead of the actual column name from summarize (which would be the function name or alias). It will cause a syntax error. The correct alias should be used in the where clause.

Full breakdown with real-world context →

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

CommonSecurityLog | where SourceIp == '10.0.0.1' | summarize totalBytes = sum(BytesSent) by bin(TimeGenerated, 5m) | where totalBytes > 100000000

Option A is correct because it first filters the CommonSecurityLog table for the specific source IP, then uses `summarize` with `bin(TimeGenerated, 5m)` to aggregate total bytes sent in 5-minute windows, and finally filters for windows where the sum exceeds 100 MB (100,000,000 bytes). This correctly implements a time-windowed aggregation to detect large outbound transfers, which is the standard pattern for identifying data exfiltration over a period.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✓
CommonSecurityLog | where SourceIp == '10.0.0.1' | summarize totalBytes = sum(BytesSent) by bin(TimeGenerated, 5m) | where totalBytes > 100000000
Why this is correct
Correct. This groups events by 5-minute windows, sums bytes sent per window, and filters those windows exceeding 100 MB (100000000 bytes).
Clue confirmation
The clue word "best" in the question point toward this answer.
Related concept
Read the scenario before looking for a memorised answer.
✗
CommonSecurityLog | where SourceIp == '10.0.0.1' | extend bin = bin(TimeGenerated, 5m) | where BytesSent > 100000000
Why it's wrong here
This filters individual events where a single BytesSent exceeds 100 MB, not the aggregate over a window. It does not sum multiple events.
✗
CommonSecurityLog | where SourceIp == '10.0.0.1' | summarize make_list(BytesSent) by TimeGenerated | where array_length(make_list) > 100000000
Why it's wrong here
make_list creates a list of values, not a sum. The where condition on array length is meaningless for byte total.
✗
CommonSecurityLog | where SourceIp == '10.0.0.1' | project BytesSent, TimeGenerated | summarize sum(BytesSent) by bin(TimeGenerated, 5m) | where sum_BytesSent > 100000000
Why it's wrong here
This is almost correct except the last where clause references 'sum_BytesSent' instead of the actual column name from summarize (which would be the function name or alias). It will cause a syntax error. The correct alias should be used in the where clause.

Common exam traps

Common exam trap: answer the scenario, not the keyword

The trap here is that candidates often confuse filtering individual events (Option B) with aggregating over a time window (Option A), or they misuse list functions (Option C) instead of sum aggregation, failing to recognize that data exfiltration detection requires cumulative byte totals over a period, not per-event thresholds.

Detailed technical explanation

How to think about this question

The `bin()` function in KQL creates fixed-size time buckets by aligning timestamps to the bucket boundary (e.g., 5-minute intervals starting at 00:00), which is essential for accurate time-windowed aggregation. The `summarize` operator groups rows by the binned time and computes the sum of `BytesSent`, producing a single row per window. In real-world exfiltration detection, attackers often spread data across multiple small packets to evade threshold-based alerts, so summing over a window is critical — a single-packet threshold (as in Option B) would miss such activity. The 100 MB threshold (100,000,000 bytes) is a common baseline for large data transfers in enterprise environments.

KKey Concepts to Remember

Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.

TExam Day Tips

Watch for words such as best, first, most likely and least administrative effort.
Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A cloud solutions architect for a retail company is evaluating services for a new workload. The correct answer here reflects best practice for the specific scenario described — not a general cloud recommendation. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Cloud exam questions reward reading the constraint carefully: the same technology can be right or wrong depending on the use case.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this SC-200 question test?

Mitigate threats using Microsoft Sentinel — This question tests Mitigate threats using Microsoft Sentinel — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: CommonSecurityLog | where SourceIp == '10.0.0.1' | summarize totalBytes = sum(BytesSent) by bin(TimeGenerated, 5m) | where totalBytes > 100000000 — Option A is correct because it first filters the CommonSecurityLog table for the specific source IP, then uses `summarize` with `bin(TimeGenerated, 5m)` to aggregate total bytes sent in 5-minute windows, and finally filters for windows where the sum exceeds 100 MB (100,000,000 bytes). This correctly implements a time-windowed aggregation to detect large outbound transfers, which is the standard pattern for identifying data exfiltration over a period.

What should I do if I get this SC-200 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

Are there clue words in this question I should notice?

Yes — watch for: "best". Signals that multiple options may be partially correct. Choose the option that most directly solves the exact problem described, not the one that sounds most complete.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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