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LFCS Essential Commands Practice Question

An administrator wants to print the last field of each line from a CSV file 'data.csv' (comma-separated). Which awk command accomplishes this?

⚠ Common exam trap

The trap here is that candidates often forget to specify the field separator with `-F,` in awk, or they confuse `cut` options (like `-f2` for a specific field instead of `$NF` for the last field), leading them to pick a command that prints a fixed column rather than the last column dynamically.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

awk -F, '{print $NF}' data.csv

`awk -F, '{print $NF}' data.csv` uses `-F,` to set the field separator to comma, and `$NF` represents the value of the last field (NF is the number of fields, so $NF is the last field). This command prints the last column of each line in the CSV file.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • awk -F, '{print $NF}' data.csv

    Why this is correct

    Correctly sets comma as field separator.

  • cut -d, -f2 data.csv

    Why it's wrong here

    Prints the second field, not the last.

  • cut -d, -f1 data.csv

    Why it's wrong here

    Prints the first field.

  • awk '{print $NF}' data.csv

    Why it's wrong here

    Uses default space separator, not comma.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This LFCS practice question is part of Courseiva's free Linux Foundation certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the LFCS exam.