Question 38 of 504
CryptographyhardMultiple ChoiceObjective-mapped

Quick Answer

The correct answer is that 65537 offers a balance between security and performance due to its low Hamming weight. This specific exponent, represented in binary as 10000000000000001, has only two bits set, which dramatically reduces the number of multiplications required during modular exponentiation compared to a random large exponent, making encryption and signature verification significantly faster while still providing strong cryptographic strength. On the Systems Security Certified Practitioner SSCP exam, this question tests your understanding of how RSA parameters are chosen to optimize real-world efficiency without compromising security—a common trap is assuming a larger exponent always means better security, when in fact the security gain is negligible beyond 65537. To remember this, think of 65537 as the “two-bit wonder”: its binary form has exactly two 1s, giving you speed and security in one compact package.

SSCP Cryptography Practice Question

This SSCP practice question tests your understanding of cryptography. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

In RSA, the public exponent e is often chosen as 65537. What is the primary reason for this choice?

Clue words in this question

Noticing these words before you look at the options changes how you read each choice.

  • Clue: "primary"

    Why it matters: Asks for the main purpose or function, not a secondary benefit. Eliminate answers that describe side-effects or partial functions.

Question 1hardmultiple choice
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Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

It offers a balance between security and performance due to low Hamming weight

Option D is correct because 65537 (0x10001) has a low Hamming weight of only 2 bits set, which makes modular exponentiation significantly faster than using a random large exponent, while still providing strong security. This choice balances computational efficiency with cryptographic strength, as a larger exponent would slow down encryption without proportional security gains.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • It ensures that the private key d is small

    Why it's wrong here

    e does not influence d size; d is computed from e and φ(n).

  • It prevents side-channel attacks

    Why it's wrong here

    Side-channel attacks are mitigated by constant-time algorithms, not exponent choice.

  • It provides the highest security level

    Why it's wrong here

    Security depends on key size, not exponent value within reason.

  • It offers a balance between security and performance due to low Hamming weight

    Why this is correct

    Few 1 bits speed up modular exponentiation.

    Clue confirmation

    The clue word "primary" in the question point toward this answer.

    Related concept

    Read the scenario before looking for a memorised answer.

Common exam traps

Common exam trap: answer the scenario, not the keyword

ISC2 often tests the misconception that a larger exponent always means higher security, when in fact the exponent's size has negligible impact on security compared to the modulus length, and the real benefit of 65537 is performance due to its low Hamming weight.

Detailed technical explanation

How to think about this question

The exponent 65537 is the fourth Fermat prime (F4 = 2^16 + 1) and is commonly recommended in PKCS#1 v2.2 and FIPS 186-4 for RSA key generation. Its binary representation (10000000000000001) has only two 1-bits, reducing the number of squaring and multiplication operations in exponentiation from O(log e) to O(Hamming weight). In practice, this speeds up encryption and signature verification by roughly 30-50% compared to a random 64-bit exponent, while avoiding the vulnerabilities of very small exponents like 3 or 17.

KKey Concepts to Remember

  • Read the scenario before looking for a memorised answer.
  • Find the constraint that changes the correct option.
  • Eliminate answers that are true in general but not in this case.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A developer is choosing between AES-256 (symmetric) and RSA-2048 (asymmetric) for encrypting a large file that will be sent to a partner. Symmetric encryption is fast but requires key exchange; asymmetric is slower but solves the key distribution problem. A hybrid approach — encrypt the file with AES, encrypt the AES key with RSA — is standard. Questions like this test whether you understand when each approach applies.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this SSCP question test?

Cryptography — This question tests Cryptography — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: It offers a balance between security and performance due to low Hamming weight — Option D is correct because 65537 (0x10001) has a low Hamming weight of only 2 bits set, which makes modular exponentiation significantly faster than using a random large exponent, while still providing strong security. This choice balances computational efficiency with cryptographic strength, as a larger exponent would slow down encryption without proportional security gains.

What should I do if I get this SSCP question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

Are there clue words in this question I should notice?

Yes — watch for: "primary". Asks for the main purpose or function, not a secondary benefit. Eliminate answers that describe side-effects or partial functions.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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Last reviewed: Jun 30, 2026

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This SSCP practice question is part of Courseiva's free ISC2 certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the SSCP exam.