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SSCP They cannot access the internet Practice Question

A user reports they cannot access the internet. The network administrator verifies that the user's workstation has an IP address of 192.168.1.100/24 and a default gateway of 192.168.1.1. The administrator can ping the default gateway but cannot ping 8.8.8.8. What is the most likely cause?

⚠ Common exam trap

Many candidates confuse 'can ping the gateway' with 'gateway has internet connectivity,' but the gateway may be reachable locally while lacking an upstream route or having a misconfigured NAT policy.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

The default gateway has no route to the internet

The administrator can ping the default gateway (192.168.1.1) but cannot ping 8.8.8.8. This indicates that Layer 2 and Layer 3 connectivity within the local subnet is working, but traffic cannot reach the internet. The most likely cause is that the default gateway does not have a route to the internet, meaning it cannot forward packets beyond its local interface to an upstream router or ISP.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Firewall is blocking outbound traffic to port 53

    Why it's wrong here

    Port 53 is DNS, not ICMP.

  • DNS server is down

    Why it's wrong here

    DNS is not required for pinging an IP address.

  • The default gateway has no route to the internet

    Why this is correct

    Local connectivity works, external fails, indicating routing issue.

  • The workstation's subnet mask is incorrect

    Why it's wrong here

    Incorrect subnet mask would affect local connectivity, but gateway is reachable.

  • The network cable is faulty

    Why it's wrong here

    Faulty cable would prevent pinging the gateway.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This SSCP practice question is part of Courseiva's free ISC2 certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the SSCP exam.