The answer is wan1, because with sla-match-mode 'any', the SD-WAN rule selects the first link that meets any single configured SLA threshold. In this scenario, wan1’s latency of 90 ms and jitter of 10 ms both fall within typical voice SLA boundaries, so it satisfies the SLA immediately and is chosen. The sla-match-mode 'any' link selection logic does not require all metrics to be met—only that at least one threshold is satisfied—and it picks the first qualifying link in the interface order. On the Fortinet NSE 4 exam, this concept tests your understanding of how SD-WAN rules prioritize link selection under different SLA strategies, and a common trap is assuming 'any' means the best overall link rather than the first acceptable one. Remember: 'any' means first to pass, not best to last.
NSE4 High Availability and Diagnostics Practice Question
This NSE4 practice question tests your understanding of high availability and diagnostics. This is a configuration task: choose the command set that satisfies every stated requirement. Small differences — like 'secret' vs 'password' or 'transport input ssh' vs 'all' — change whether the answer is correct. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Exhibit
Refer to the exhibit.
config system sdwan
set status enable
config members
edit 1
set interface "wan1"
set gateway 10.0.0.254
set source 10.0.0.1
next
edit 2
set interface "wan2"
set gateway 10.0.1.254
set source 10.0.1.1
next
end
config performance-sla
edit 1
set name "sla1"
set server "8.8.8.8"
set protocol "ping"
set probe-packets 5
set latency-threshold 100
set jitter-threshold 20
next
end
config service
edit 1
set name "voice"
set mode sla
set sla-match-mode any
config sla
edit "sla1"
set id 1
next
end
set priority-members 1 2
next
end
end
Refer to the exhibit. An SD-WAN rule for voice traffic uses the SLA strategy with sla-match-mode 'any'. SLA 'sla1' measures ping to 8.8.8.8. If wan1 has latency 90 ms and jitter 10 ms, and wan2 has latency 110 ms and jitter 5 ms, which link will be selected for voice traffic?
Refer to the exhibit.
config system sdwan
set status enable
config members
edit 1
set interface "wan1"
set gateway 10.0.0.254
set source 10.0.0.1
next
edit 2
set interface "wan2"
set gateway 10.0.1.254
set source 10.0.1.1
next
end
config performance-sla
edit 1
set name "sla1"
set server "8.8.8.8"
set protocol "ping"
set probe-packets 5
set latency-threshold 100
set jitter-threshold 20
next
end
config service
edit 1
set name "voice"
set mode sla
set sla-match-mode any
config sla
edit "sla1"
set id 1
next
end
set priority-members 1 2
next
end
end
A
Neither link, because both fail jitter?
Why wrong: Incorrect; both jitter values are below threshold.
B
wan1, because it meets the SLA thresholds.
Correct; wan1 meets both latency and jitter thresholds.
C
Both links, because sla-match-mode 'any' allows any link that meets SLA.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
wan1, because it meets the SLA thresholds.
With sla-match-mode 'any', the SD-WAN rule selects the first link that meets any of the configured SLA thresholds. The SLA for voice traffic measures ping to 8.8.8.8 with thresholds for latency and jitter. wan1 has latency 90 ms and jitter 10 ms, which both fall within typical SLA thresholds (e.g., latency < 150 ms, jitter < 20 ms), so it meets the SLA. wan2 has latency 110 ms, which also meets the latency threshold, but since 'any' mode selects the first qualifying link, wan1 is chosen. Option B is correct because wan1 satisfies the SLA and is selected first.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
Neither link, because both fail jitter?
Why it's wrong here
Incorrect; both jitter values are below threshold.
✓
wan1, because it meets the SLA thresholds.
Why this is correct
Correct; wan1 meets both latency and jitter thresholds.
Related concept
Read the scenario before looking for a memorised answer.
✗
Both links, because sla-match-mode 'any' allows any link that meets SLA.
Why it's wrong here
Incorrect; only wan1 meets SLA.
✗
wan2, because it has lower jitter.
Why it's wrong here
Incorrect; wan2 fails latency threshold.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often assume sla-match-mode 'any' selects all links that meet any SLA, but it actually selects only the first qualifying link in the order, leading to confusion with 'all' mode or load-balancing behavior.
Detailed technical explanation
How to think about this question
In Fortinet SD-WAN, SLA thresholds are configured per link and measured using probes (e.g., ping to 8.8.8.8). The sla-match-mode 'any' means the rule will use the first link in the ordered list that meets any of the defined SLA metrics (latency, jitter, packet loss). This is different from 'all' mode, which requires all metrics to be met. Under the hood, FortiOS evaluates links sequentially based on the configured strategy, and the first link that satisfies the SLA is selected, ignoring subsequent links even if they also meet thresholds.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the NSE4 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
High Availability and Diagnostics — This question tests High Availability and Diagnostics — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: wan1, because it meets the SLA thresholds. — With sla-match-mode 'any', the SD-WAN rule selects the first link that meets any of the configured SLA thresholds. The SLA for voice traffic measures ping to 8.8.8.8 with thresholds for latency and jitter. wan1 has latency 90 ms and jitter 10 ms, which both fall within typical SLA thresholds (e.g., latency < 150 ms, jitter < 20 ms), so it meets the SLA. wan2 has latency 110 ms, which also meets the latency threshold, but since 'any' mode selects the first qualifying link, wan1 is chosen. Option B is correct because wan1 satisfies the SLA and is selected first.
What should I do if I get this NSE4 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Question Discussion
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