Courseiva
hardMultiple ChoiceObjective-mapped

FC0-U71 Practice Question: Refer to the exhibit

Exhibit

Refer to the exhibit.

Device: Router
Interface: GigabitEthernet0/0
IP Address: 10.0.0.1
Subnet Mask: 255.255.255.0
Status: Administratively down

Interface: GigabitEthernet0/1
IP Address: 192.168.1.1
Subnet Mask: 255.255.255.0
Status: up/up

Refer to the exhibit. A technician is troubleshooting connectivity from a PC connected to the 192.168.1.0/24 network. The PC cannot reach the 10.0.0.0/24 network. What is the most likely cause?

⚠ Common exam trap

CompTIA often tests the concept that a disabled interface on the local subnet is the most fundamental cause of connectivity failure, tricking candidates into focusing on routing or cabling issues on the remote side instead of verifying the local interface status first.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

GigabitEthernet0/0 is disabled

The PC on 192.168.1.0/24 cannot reach 10.0.0.0/24 because GigabitEthernet0/0 is disabled, which is the interface that provides the default gateway or the path to the router. Without an active interface on the local subnet, the PC cannot send any frames to the router, and no traffic can leave the local network. Even if routes exist, a disabled interface prevents all Layer 1 and Layer 2 communication, making connectivity impossible.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Incorrect subnet mask on the PC

    Why it's wrong here

    The exhibit shows router interfaces, not PC.

  • Missing route to 10.0.0.0/24

    Why it's wrong here

    The interface being down would prevent connectivity regardless of routing.

  • Faulty cable on GigabitEthernet0/1

    Why it's wrong here

    That interface is up/up.

  • GigabitEthernet0/0 is disabled

    Why this is correct

    The interface is administratively down.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

About these practice questions

Courseiva writes every FC0-U71 question from scratch — 988 in total, each with an explanation and a wrong-answer breakdown. None are copied from real exams or dumps. Learn why practice questions differ from exam dumps →

How Courseiva writes practice questions · Editorial policy

JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This FC0-U71 practice question is part of Courseiva's free CompTIA certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the FC0-U71 exam.