This FC0-U61 practice question tests your understanding of database fundamentals. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Refer to the exhibit. A database administrator runs the following query:
SELECT c.Name, SUM(o.Quantity) AS TotalItems FROM Customers c LEFT JOIN Orders o ON c.ID = o.CustomerID GROUP BY c.Name;
What is the result for 'Alice'?
2
Why wrong: This is the quantity of only the Laptop order.
NULL
Why wrong: NULL would appear only if Alice had no orders, but she has two.
5
Why wrong: This is the quantity of only the Mouse order.
7
SUM of both orders (2+5=7).
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
7
The LEFT JOIN ensures that Alice's record from the Customers table is retained even if there are no matching rows in Orders. The SUM(o.Quantity) aggregates the Quantity values from the joined Orders rows for Alice. Since Alice has two orders with quantities 2 and 5, the sum is 7, making option D correct.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
2
Why it's wrong here
This is the quantity of only the Laptop order.
NULL
Why it's wrong here
NULL would appear only if Alice had no orders, but she has two.
5
Why it's wrong here
This is the quantity of only the Mouse order.
7
Why this is correct
SUM of both orders (2+5=7).
Related concept
Read the scenario before looking for a memorised answer.
Common exam traps
The trap here is that candidates may mistakenly pick the quantity of a single order (2 or 5) instead of computing the SUM, or incorrectly assume that a LEFT JOIN would produce NULL for Alice when she actually has matching orders.
Detailed technical explanation
In SQL, a LEFT JOIN returns all rows from the left table (Customers) and matching rows from the right table (Orders); non-matching rows yield NULL for right-table columns. The GROUP BY clause groups results by c.Name, and SUM() aggregates the Quantity column across each group. If a customer had no orders, SUM() would return NULL (or 0 depending on the DBMS), but here Alice has orders, so the sum is computed as 2 + 5 = 7.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the FC0-U61 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Database Fundamentals — This question tests Database Fundamentals — Read the scenario before looking for a memorised answer..
The correct answer is: 7 — The LEFT JOIN ensures that Alice's record from the Customers table is retained even if there are no matching rows in Orders. The SUM(o.Quantity) aggregates the Quantity values from the joined Orders rows for Alice. Since Alice has two orders with quantities 2 and 5, the sum is 7, making option D correct.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 11, 2026
This FC0-U61 practice question is part of Courseiva's free CompTIA certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the FC0-U61 exam.
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