A network technician is configuring a device and needs to enter a MAC address. Which of the following is a valid MAC address in hexadecimal notation?
3A:4B:5C:6D:7E:8F is valid because a MAC address comprises six octets, each written as two hexadecimal digits separated by colons. Every character here falls within 0–9 or A–F, satisfying the stem's hexadecimal notation requirement, and the total of twelve digits matches the 48-bit hardware address format.
Why this answer
A valid MAC address consists of 48 bits represented as six groups of two hexadecimal digits separated by colons or hyphens. Option C (3A:4B:5C:6D:7E:8F) uses only valid hexadecimal characters (0-9, A-F) in the correct six-octet format, making it a legitimate MAC address.
Exam trap
FC0-U71 often tests whether candidates recognize that hexadecimal only includes 0-9 and A-F, and that a full MAC requires six octets — not three.
How to eliminate wrong answers
Option A is wrong because it contains characters G through L, which are not valid hexadecimal digits (hex only uses 0-9 and A-F). Option B is wrong because AB:CD:EF contains only three octets (24 bits), which is the format of an OUI prefix, not a full 48-bit MAC address. Option D is wrong because it contains invalid hex characters (X, Z, Y, W, V) and uses an '0X' prefix that is not part of MAC address notation.