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300-410 Practice Question: Runs the following command to troubleshoot a…

A network engineer runs the following command to troubleshoot a VRF-Lite issue:

R1# show ip eigrp vrf CUSTOMER_B topology 10.1.1.0/24

Output: IP-EIGRP (AS 100): Topology entry for 10.1.1.0/24 for VRF CUSTOMER_B State is Passive, Query origin flag is 1, 1 Successor(s), FD is 131072 Routing Descriptor Blocks:

10.1.1.1 (GigabitEthernet0/1), from 10.1.1.1, Send flag is 0x0

Composite metric is (131072/128256), Route is Internal Vector metric: Minimum bandwidth is 100000 Kbit Total delay is 100 microseconds Reliability is 255/255 Load is 1/255 Minimum MTU is 1500 Hop count is 1

What does this output indicate?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

The route 10.1.1.0/24 has one successor with a feasible distance of 131072 and is learned via 10.1.1.1.

The 'show ip eigrp vrf topology' command displays the EIGRP topology table entry for a specific prefix within a VRF. The output shows the route 10.1.1.0/24 is in Passive state, meaning no EIGRP query is pending. It has one successor (the best path) with a feasible distance (FD) of 131072. The next hop is 10.1.1.1 via GigabitEthernet0/1.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • The route 10.1.1.0/24 is in Active state, indicating an EIGRP query is in progress.

    Why it's wrong here

    Incorrect. The state is Passive, not Active.

  • The route 10.1.1.0/24 has one successor with a feasible distance of 131072 and is learned via 10.1.1.1.

    Why this is correct

    Correct. The output shows one successor, FD 131072, and next hop 10.1.1.1.

  • The route 10.1.1.0/24 is an external EIGRP route redistributed into the VRF.

    Why it's wrong here

    Incorrect. The output says 'Route is Internal', not external.

  • The route 10.1.1.0/24 has multiple successors due to equal-cost paths.

    Why it's wrong here

    Incorrect. There is only one successor listed in the Routing Descriptor Blocks.

Visual reference

PC R1 R2 R3 Server hop 1 hop 2 hop 3 RIP metric = 3 hops — lowest hop count wins

Quick reference

Routing Protocol Comparison

ProtocolMetricMax HopsAlgorithmType
RIP v2Hop count15Bellman-FordDistance vector
OSPFCost (bandwidth)UnlimitedDijkstra (SPF)Link state
EIGRPComposite metricUnlimitedDUALHybrid
IS-ISCostUnlimitedDijkstraLink state
BGPPolicy / attributesUnlimitedPath vectorPath vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 300-410 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 300-410 exam.