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300-410 Practice Question: Examine the following partial configuration on…

Examine the following partial configuration on R1:

!--- R1 configuration route-map RMAP permit 10 match ip address prefix-list PL-1 set metric 100 ! route-map RMAP permit 20 set metric 200 !

router eigrp 100
 network 10.0.0.0

redistribute ospf 1 metric 1000 100 255 1 1500 route-map RMAP !

What is the effect of this configuration?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

Routes matching prefix-list PL-1 are redistributed with metric 100; all other OSPF routes are redistributed with metric 200.

The route-map RMAP has two permit sequences. The first matches prefix-list PL-1 and sets metric to 100. The second is a catch-all permit with no match, setting metric to 200. All redistributed OSPF routes will match either sequence and have their metric set accordingly. If a route matches the first sequence, its metric is set to 100; otherwise, it matches the second and gets metric 200. There is no deny sequence, so no routes are filtered.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✗

    Only routes matching prefix-list PL-1 are redistributed into EIGRP with metric 100; all other OSPF routes are denied.

    Why it's wrong here

    Route-map permit 20 has no match statement, so it matches all remaining OSPF routes and sets metric 200; they are redistributed, not denied. It is tempting because an unmatched route-map sequence implies filtering, and would be correct if sequence 20 were a deny statement, but permit 20 accepts everything.

  • ✓

    Routes matching prefix-list PL-1 are redistributed with metric 100; all other OSPF routes are redistributed with metric 200.

    Why this is correct

    Route-map RMAP is evaluated sequentially: permit sequence 10 matches prefix-list PL-1 and sets metric 100, while sequence 20 has no match clause, so it permits all remaining OSPF routes and sets metric 200. Both sequences redistribute into EIGRP 100.

  • ✗

    The route-map is missing a deny statement; without it, all routes are permitted with default metric.

    Why it's wrong here

    Route-map entries are permit statements, so unmatched traffic hits the implicit deny at the end; no explicit deny is needed. The tempting belief that a missing deny causes default-metric permits confuses route-maps with ACLs, where an implicit deny also terminates processing. Permit 20 sets metric 200 for other routes.

  • ✗

    The route-map is applied to redistribution, but the metric values are ignored because redistribute command also specifies metric.

    Why it's wrong here

    The route-map's set metric clauses override the redistribute command's seed metric for matched routes, so metrics are not ignored. It is tempting because redistribute metric parameters normally supply the seed, and would apply where no route-map set metric exists, but here permit 10 and permit 20 both set metrics explicitly.

Visual reference

R1 R2 R3 R4 10 100 10 100 OSPF picks R1→R2→R4 (cost 20) over R1→R3→R4 (cost 200)

Quick reference

Routing Protocol Comparison

ProtocolMetricMax HopsAlgorithmType
RIP v2Hop count15Bellman-FordDistance vector
OSPFCost (bandwidth)UnlimitedDijkstra (SPF)Link state
EIGRPComposite metricUnlimitedDUALHybrid
IS-ISCostUnlimitedDijkstraLink state
BGPPolicy / attributesUnlimitedPath vectorPath vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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