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300-410 Practice Question: Configures PBR on a router to route traffic from…

A network engineer configures PBR on a router to route traffic from subnet 10.1.1.0/24 via next-hop 192.168.1.2. The route-map uses match ip address and set ip next-hop commands. However, traffic sourced from 10.1.1.5 still follows the routing table instead of the PBR policy. What is the most likely cause?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

The router is generating the traffic locally (e.g., ping from the router), and PBR does not apply to local packets without 'ip local policy route-map'.

PBR processes only transit traffic; locally generated packets (e.g., from the router itself) are not affected by PBR unless the 'ip local policy route-map' command is used. The engineer must apply PBR globally for local packets.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • The route-map is applied to the wrong interface (outbound instead of inbound).

    Why it's wrong here

    PBR is applied inbound; applying outbound would not affect incoming traffic.

  • The router is generating the traffic locally (e.g., ping from the router), and PBR does not apply to local packets without 'ip local policy route-map'.

    Why this is correct

    Local packets require 'ip local policy route-map' to be influenced by PBR.

  • The ACL in the route-map is missing a permit statement for subnet 10.1.1.0/24.

    Why it's wrong here

    If the ACL were missing, no traffic would match, but the symptom points to local traffic.

  • The next-hop 192.168.1.2 is not reachable via any directly connected interface.

    Why it's wrong here

    Unreachable next-hop would cause PBR to fall back to routing table, but the issue is specific to local traffic.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 300-410 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 300-410 exam.