hardMultiple ChoiceObjective-mapped
300-410 Practice Question: Runs the following command on Router R1: R1# show…
A network engineer runs the following command on Router R1:
R1# show ip policy Interface Route-map
GigabitEthernet0/0 PBR-MULTI
R1# show route-map PBR-MULTI
route-map PBR-MULTI, permit, sequence 10 Match clauses:
ip address (access-lists): 140
Set clauses:
ip next-hop 10.0.0.2 10.0.0.3
Policy routing matches: 200 packets, 18000 bytes
R1# show ip route 10.0.0.2
Routing entry for 10.0.0.2/32 Known via "eigrp 1", distance 90, metric 28160 Last update from 192.168.1.2 on GigabitEthernet0/1
R1# show ip route 10.0.0.3
% Network not in routing table
Based on this output, what is the most likely behavior for packets matching ACL 140?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Packets are forwarded to 10.0.0.2.
When multiple next-hops are specified in a set clause, PBR tries them in order. The first reachable next-hop is used. Here, 10.0.0.2 is reachable, so packets are forwarded to 10.0.0.2. The second next-hop is not reachable, but that does not affect the first.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Packets are load-balanced between 10.0.0.2 and 10.0.0.3.
Why it's wrong here
PBR does not load-balance across multiple next-hops; it uses the first reachable one.
- ✓
Packets are forwarded to 10.0.0.2.
Why this is correct
Since 10.0.0.2 is reachable, PBR uses it. The unreachable 10.0.0.3 is ignored.
- ✗
Packets are dropped because one next-hop is unreachable.
Why it's wrong here
PBR uses the first reachable next-hop; unreachable ones are skipped.
- ✗
Packets are forwarded to 10.0.0.3 via a recursive lookup.
Why it's wrong here
10.0.0.3 is not in the routing table, so it cannot be used.
Visual reference
Quick reference
Routing Protocol Comparison
| Protocol | Metric | Max Hops | Algorithm | Type |
|---|---|---|---|---|
| RIP v2 | Hop count | 15 | Bellman-Ford | Distance vector |
| OSPF | Cost (bandwidth) | Unlimited | Dijkstra (SPF) | Link state |
| EIGRP | Composite metric | Unlimited | DUAL | Hybrid |
| IS-IS | Cost | Unlimited | Dijkstra | Link state |
| BGP | Policy / attributes | Unlimited | Path vector | Path vector |
RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.
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JA
Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
This 300-410 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 300-410 exam.