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300-410 Practice Question: Runs the following command on Router R1: R1# show…

A network engineer runs the following command on Router R1:

R1# show mpls ldp neighbor

Peer LDP Ident: 192.168.1.2:0, Local LDP Ident: 192.168.0.1:0 TCP connection: 192.168.1.2.646 - 192.168.0.1.49876 State: Oper; Msgs sent/rcvd: 100/105; Downstream on demand Up time: 00:10:30 LDP discovery sources: GigabitEthernet0/0, Src IP addr: 192.168.1.2 Addresses bound to peer LDP Ident:

192.168.1.2        10.1.1.2

Based on this output, what is the state of the LDP session?

⚠ Common exam trap

Cisco often tests the misconception that 'Downstream on demand' is a problem or that any mention of 'downstream' implies a failure, when in fact it is a standard operational mode for LDP.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

The LDP session is operational and exchanging label information.

The output shows 'State: Oper', which means the LDP session is operational. The 'Downstream on demand' label distribution mode is a valid mode (RFC 5036) and does not indicate a problem. The session is exchanging label information, as evidenced by the 'Oper' state and the presence of peer addresses.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • The LDP session is down due to a TCP connection issue.

    Why it's wrong here

    The state is Oper, meaning it is up.

  • The LDP session is operational and exchanging label information.

    Why this is correct

    State Oper indicates the session is up and running.

  • The LDP session is in the process of being established.

    Why it's wrong here

    Oper is not a transitional state.

  • The LDP session is using downstream on demand mode, which is a problem.

    Why it's wrong here

    Downstream on demand is a valid mode.

Visual reference

Client Server SYN (seq=100) SYN-ACK (seq=200, ack=101) ACK (ack=201) Connection established — data transfer begins

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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