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300-410 Practice Question: Runs the following command on Router R1: R1# show…

A network engineer runs the following command on Router R1:

R1# show bgp ipv4 unicast 10.3.3.0/24

BGP routing table entry for 10.3.3.0/24, version 10 Paths: (2 available, best #2, table default) Advertised to update-groups: 1 Refresh Epoch 1 65003 65004

10.1.13.3 from 10.1.13.3 (10.3.3.3)

Origin IGP, metric 0, localpref 100, valid, external rx pathid: 0, tx pathid: 0 Refresh Epoch 1 65005

10.1.15.5 from 10.1.15.5 (10.5.5.5)

Origin IGP, metric 0, localpref 200, valid, external, best rx pathid: 0, tx pathid: 0x0

Based on this output, why is the path via 10.1.15.5 chosen as best?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

Because it has a higher local preference of 200.

BGP selects the best path based on several criteria. Here, both paths are external, valid, and have the same weight (default 0). The path via 10.1.15.5 has a higher local preference (200 vs 100), which is the first tiebreaker after weight. Therefore, it is chosen as best.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Because it has a shorter AS path (65005 vs 65003 65004).

    Why it's wrong here

    AS path length is considered after local preference, but local preference is the deciding factor here.

  • Because it has a higher local preference of 200.

    Why this is correct

    Local preference is compared before AS path length. The path with localpref 200 is preferred over 100.

  • Because it has a lower metric (0 vs 0).

    Why it's wrong here

    Metrics are equal (0), so this does not determine the best path.

  • Because it was learned from a lower neighbor IP address.

    Why it's wrong here

    Neighbor IP is a later tiebreaker and not needed here.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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