CCNA Network Infrastructure and Connectivity Practice Question
A host has the address 10.10.10.94/27. Which subnet contains that host?
⚠ Common exam trap
Avoid guessing based on familiar numbers; calculate the subnet range using the block size.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
10.10.10.64/27
A /27 mask creates subnets in blocks of 32 addresses. In plain language, that means the fourth-octet ranges are 0–31, 32–63, 64–95, 96–127, and so on. Since the host address ends in 94, it falls inside the 64–95 block. That means the subnet is 10.10.10.64/27. This is a classic subnetting task because it checks whether you can move from prefix length to block size and then locate the host inside the correct range. The key skill is recognizing the increment boundary and not guessing based only on the nearest familiar address.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
10.10.10.32/27
Why it's wrong here
The 10.10.10.32/27 subnet spans addresses 32 through 63, with 32 as the network ID and 63 as the broadcast. The host address 10.10.10.94 is 31 addresses above the end of this range, placing it in the next /27 block. Because a /27 block size is exactly 32, 94 falls in the subnet whose network address is 64, not 32.
When this WOULD be correct
If the question asked which subnet contains the address 10.10.10.32 or any address within the range of 10.10.10.32 to 10.10.10.63, then option A would be the correct answer, as it would directly correspond to that subnet.
- ✓
10.10.10.64/27
Why this is correct
A /27 prefix length creates 32-address subnets. To find the subnet containing 10.10.10.94, divide 94 by 32, which gives 2.9375; the network address is the floor of that quotient multiplied by 32, i.e., 2 × 32 = 64. Thus 10.10.10.64/27 covers 64 through 95, and 94 is a valid host in that range (usable addresses 65–94, broadcast 95).
- ✗
10.10.10.96/27
Why it's wrong here
The 10.10.10.96/27 subnet starts at network address 96 and includes addresses 96 through 127, so it begins one address above the host we are checking. Since 10.10.10.94 is the last usable host address of the subnet ending at 95, it falls just before this subnet's boundary. In other words, 94 is in the previous /27 block (64/27), not in the 96/27 block.
When this WOULD be correct
If the question asked for the subnet that includes the address 10.10.10.96 specifically, then option C would be correct, as it would represent the subnet containing that address.
- ✗
10.10.10.0/27
Why it's wrong here
The 10.10.10.0/27 subnet covers addresses 0 through 31, with 0 as the network ID and 31 as the broadcast. The host 10.10.10.94 is far above that entire range; it lies in the third /27 block, which begins at 64. To contain 94, a /27 subnet would need its network address to be 64, not 0.
When this WOULD be correct
If the question asked for the subnet that contains the address 10.10.10.0 itself, or if it specified the network address for a different subnetting scheme that included 10.10.10.0, then option D would be correct.
Option-by-option analysis
Why each answer is right or wrong
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
✓10.10.10.64/27Correct answer▾
Why this is correct
A /27 prefix length creates 32-address subnets. To find the subnet containing 10.10.10.94, divide 94 by 32, which gives 2.9375; the network address is the floor of that quotient multiplied by 32, i.e., 2 × 32 = 64. Thus 10.10.10.64/27 covers 64 through 95, and 94 is a valid host in that range (usable addresses 65–94, broadcast 95).
✗10.10.10.32/27Wrong answer — click to see why▾
Why this is wrong here
The subnet 10.10.10.32/27 covers addresses 10.10.10.32 through 10.10.10.63. The host address 10.10.10.94 is not within this range, so this subnet is incorrect.
★ When this WOULD be the correct answer
If the question asked which subnet contains the address 10.10.10.32 or any address within the range of 10.10.10.32 to 10.10.10.63, then option A would be the correct answer, as it would directly correspond to that subnet.
Why candidates choose this
Students might mistakenly think that because 94 is close to 64, it could be in the 32/27 subnet, but they forget that the subnet boundaries are multiples of 32.
✗10.10.10.96/27Wrong answer — click to see why▾
Why this is wrong here
The subnet 10.10.10.96/27 covers addresses 10.10.10.96 through 10.10.10.127. The host address 10.10.10.94 is below the starting address of this subnet, so it is not included.
★ When this WOULD be the correct answer
If the question asked for the subnet that includes the address 10.10.10.96 specifically, then option C would be correct, as it would represent the subnet containing that address.
Why candidates choose this
Students might incorrectly assume that 94 is close to 96 and could be in that subnet, but they overlook that the subnet starts at 96, not 94.
✗10.10.10.0/27Wrong answer — click to see why▾
Why this is wrong here
The subnet 10.10.10.0/27 covers addresses 10.10.10.0 through 10.10.10.31. The host address 10.10.10.94 is far outside this range, so this subnet is incorrect.
★ When this WOULD be the correct answer
If the question asked for the subnet that contains the address 10.10.10.0 itself, or if it specified the network address for a different subnetting scheme that included 10.10.10.0, then option D would be correct.
Why candidates choose this
Students might think that any address starting with 10.10.10 could be in the 0/27 subnet, but they fail to consider the subnet mask and the resulting address range.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Visual reference
Quick reference
Routing Protocol Comparison
| Protocol | Metric | Max Hops | Algorithm | Type |
|---|---|---|---|---|
| RIP v2 | Hop count | 15 | Bellman-Ford | Distance vector |
| OSPF | Cost (bandwidth) | Unlimited | Dijkstra (SPF) | Link state |
| EIGRP | Composite metric | Unlimited | DUAL | Hybrid |
| IS-IS | Cost | Unlimited | Dijkstra | Link state |
| BGP | Policy / attributes | Unlimited | Path vector | Path vector |
RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.
Go deeper
Related to this question
Learn chapter
IPv4 Addressing and Address Classes
Key term
Prefix length
A prefix length is the number of bits in a subnet mask that identifies the network portion of an IP address, written after a slash (e.g., /24).
Key term
Block size
Block size is the amount of data, measured in bytes, that a system reads or writes in a single operation, affecting storage efficiency and network performance.
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JA
Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
This 200-301 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-301 exam.