Quick Answer
The answer is 10.10.10.63. This is correct because the /27 subnet mask uses a block size of 32 addresses, and the host IP 10.10.10.33 falls within the 32–63 range; the broadcast address is always the last address in that block, which is 10.10.10.63. On the CCNA 200-301 v2 exam, this type of question tests your ability to quickly identify subnet boundaries and calculate the broadcast address from an IP and subnet mask, a fundamental skill for troubleshooting and network design. A common trap is forgetting that the subnet itself starts on a multiple of the block size—here, 32—so .33 is not the network address. To find the broadcast address from IP and subnet mask, first determine the block size (256 minus the mask’s interesting octet value), then find the subnet boundary the host belongs to, and finally subtract one from the next subnet’s network address. Memory tip: think of the block size as a “jump”—once you know the jump, the broadcast is always the last address before the next jump.
This 200-301 practice question tests your understanding of network infrastructure and connectivity. This is a configuration task: choose the command set that satisfies every stated requirement. Small differences — like 'secret' vs 'password' or 'transport input ssh' vs 'all' — change whether the answer is correct. A key principle to apply: a /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses.. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A host is configured with 10.10.10.33/27. What is the broadcast address of its subnet?
10.10.10.31
Why wrong: This is wrong because .31 is the broadcast of the previous /27 block.
10.10.10.63
This is correct because .33 is in the 32–63 subnet.
10.10.10.32
Why wrong: This is wrong because .32 is the network address of the block.
10.10.10.64
Why wrong: This is wrong because .64 is the start of the next subnet.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
10.10.10.63
A /27 uses address blocks of 32. In practical terms, the ranges are 0–31, 32–63, 64–95, and so on. Because .33 falls inside the 32–63 block, the broadcast address is the last address in that block, which is 10.10.10.63. This is a classic subnet-boundary question. The trick is to identify the correct block first and then choose its last address as the broadcast.
Key principle: A /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
10.10.10.31
Why it's wrong here
This is wrong because .31 is the broadcast of the previous /27 block.
When this WOULD be correct
If the question were to ask for the broadcast address of the subnet 10.10.10.0/27, then 10.10.10.31 would be the correct answer, as it is the highest address in that subnet range.
10.10.10.63
Why this is correct
This is correct because .33 is in the 32–63 subnet.
Related concept
A /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses.
10.10.10.32
Why it's wrong here
This is wrong because .32 is the network address of the block.
When this WOULD be correct
In a different question where the subnet mask is /26 and the host IP is 10.10.10.33, option C (10.10.10.32) would be the correct answer, as it would then represent the network address of that subnet.
10.10.10.64
Why it's wrong here
This is wrong because .64 is the start of the next subnet.
When this WOULD be correct
If the question specified a different subnet mask, such as /26, then the broadcast address would be 10.10.10.63, making option D (10.10.10.64) the next valid address in that subnet, which could be considered for a different context.
Option-by-option analysis
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
Why this is correct
This is correct because .33 is in the 32–63 subnet.
Why this is wrong here
10.10.10.31 is the broadcast address of the previous /27 subnet (10.10.10.0–10.10.10.31), not the subnet containing .33.
★ When this WOULD be the correct answer
If the question were to ask for the broadcast address of the subnet 10.10.10.0/27, then 10.10.10.31 would be the correct answer, as it is the highest address in that subnet range.
Why candidates choose this
Students often mistakenly think that because .33 is close to .31, the broadcast might be .31, or they confuse the network address with the broadcast address.
Why this is wrong here
10.10.10.32 is the network address (subnet ID) of the subnet containing .33, not the broadcast address. The network address is the first address in the block.
★ When this WOULD be the correct answer
In a different question where the subnet mask is /26 and the host IP is 10.10.10.33, option C (10.10.10.32) would be the correct answer, as it would then represent the network address of that subnet.
Why candidates choose this
Students may incorrectly assume that the network address is the broadcast address, especially when they see that .32 is the start of the subnet and .33 is the first usable host.
Why this is wrong here
10.10.10.64 is the network address of the next /27 subnet (10.10.10.64–10.10.10.95), not the broadcast address of the subnet containing .33.
★ When this WOULD be the correct answer
If the question specified a different subnet mask, such as /26, then the broadcast address would be 10.10.10.63, making option D (10.10.10.64) the next valid address in that subnet, which could be considered for a different context.
Why candidates choose this
Students might think that because .33 is near the end of the block, the broadcast could be the next network address, or they may miscalculate the block boundaries.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Common exam traps
Don't confuse the network address or the next subnet's start with the broadcast address. Always calculate the correct range first.
Detailed technical explanation
Subnetting is a fundamental concept in IP networking that divides a larger network into smaller, manageable sub-networks or subnets. A /27 subnet mask means that the first 27 bits of the IP address are used for the network portion, leaving 5 bits for host addresses. This results in 32 IP addresses per subnet, including network and broadcast addresses. The subnet mask for /27 is 255.255.255.224, which defines the block size and address range for each subnet. To determine the broadcast address of a subnet, you first identify the subnet block in which the host IP resides. For a /27 subnet, address blocks increment by 32 (e.g., 0–31, 32–63, 64–95). The broadcast address is always the highest address in the subnet block. Since 10.10.10.33 falls within the 32–63 range, the broadcast address is 10.10.10.63. This address is reserved for broadcasting to all hosts within that subnet. A common exam trap is confusing the network address, broadcast address, and usable host addresses within a subnet. For example, 10.10.10.32 is the network address of the subnet containing 10.10.10.33, not the broadcast. Similarly, 10.10.10.31 is the broadcast of the previous subnet block (0–31), not the current one. Understanding these boundaries is critical for subnetting questions on the CCNA exam and for practical network design and troubleshooting.
Key takeaway
A /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses.
Real-world example
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
What to study next
Review a /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
Network Infrastructure and Connectivity — study guide chapter
Learn the concepts, then practise the questions
Network Infrastructure and Connectivity practice questions
Targeted practice on this topic area only
All 200-301 questions
1,819 questions across all exam domains
CCNA 200-301 v2 study guide
Full concept coverage aligned to exam objectives
200-301 practice test guide
How to use practice tests most effectively before exam day
Related practice questions
Use these pages to review the topic behind this question. This is how one missed question becomes focused revision.
Practise 200-301 questions linked to Network Infrastructure and Connectivity.
Practise 200-301 questions linked to Switching and Network Access.
Practise 200-301 questions linked to IP Routing.
Practise 200-301 questions linked to Network Services and Security.
Practise 200-301 questions linked to AI and Network Operations.
Practise IPv4 subnetting, CIDR, masks, host ranges and subnet selection.
Practise OSPF neighbours, router IDs, metrics, areas and routing-table interpretation.
Practise VLANs, access ports, trunks, allowed VLANs and switching scenarios.
Practise spanning tree, root bridge election, port roles and STP troubleshooting.
Practise LACP, PAgP, port-channel behaviour and bundle requirements.
Practise standard and extended ACLs, permit/deny logic and traffic filtering.
Practise static NAT, dynamic NAT, PAT and inside/outside address translation.
Practice this exam
Short sessions build daily habit. Longer sessions build exam-day stamina. Try a timed session to simulate real conditions.
FAQ
Network Infrastructure and Connectivity — This question tests Network Infrastructure and Connectivity — A /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses..
The correct answer is: 10.10.10.63 — A /27 uses address blocks of 32. In practical terms, the ranges are 0–31, 32–63, 64–95, and so on. Because .33 falls inside the 32–63 block, the broadcast address is the last address in that block, which is 10.10.10.63. This is a classic subnet-boundary question. The trick is to identify the correct block first and then choose its last address as the broadcast.
Review a /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
A /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Same concept, more angles
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. An interface is configured with 10.24.7.158/27. What is the broadcast address of that subnet?
hardWhy A: A /27 uses blocks of 32 addresses. The block containing .158 is 10.24.7.128 through 10.24.7.159, so .159 is the broadcast address.
Last reviewed: May 17, 2026
This 200-301 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-301 exam.
Question Discussion
Share a tip, memory trick, or ask about the reasoning behind this question. Do not post real exam questions, leaked content, braindumps, or copyrighted exam material. Comments are moderated and may be removed without notice.
Sign in to join the discussion.