This 200-301 practice question tests your understanding of network infrastructure and connectivity. Match the stated requirement to the specific cloud service, access model, or configuration option — many options are valid in isolation but not for this scenario. A key principle to apply: a /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely.. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A subnet has the network address 192.168.30.0/26. What is the broadcast address?
192.168.30.63
This is correct because the .0/26 block ends at .63.
192.168.30.64
Why wrong: This is wrong because .64 is the first address of the next /26 block.
192.168.30.255
Why wrong: This is wrong because that would be the broadcast of the full /24, not the /26 subnet.
192.168.30.31
Why wrong: This is wrong because .31 would be the broadcast of a smaller /27 block.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
192.168.30.63
A /26 subnet contains 64 addresses. In plain language, the block that starts at 192.168.30.0 runs through 192.168.30.63. The first address is the network address and the last address is the broadcast address, so the broadcast for this subnet is 192.168.30.63. This is a standard subnet-boundary calculation. Once the block size is identified, the broadcast address is simply the final address in that block.
Key principle: A /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
192.168.30.63
Why this is correct
This is correct because the .0/26 block ends at .63.
Related concept
A /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely.
192.168.30.64
Why it's wrong here
This is wrong because .64 is the first address of the next /26 block.
When this WOULD be correct
If the question asked for the first usable IP address of the subnet 192.168.30.0/26, then option B (192.168.30.64) would be correct, as it is the first address of the subsequent subnet after the specified range.
192.168.30.255
Why it's wrong here
This is wrong because that would be the broadcast of the full /24, not the /26 subnet.
When this WOULD be correct
If the question were about a subnet with the network address 192.168.30.0/24, then 192.168.30.255 would be the correct broadcast address, as this subnet includes all addresses from 192.168.30.0 to 192.168.30.255.
192.168.30.31
Why it's wrong here
This is wrong because .31 would be the broadcast of a smaller /27 block.
When this WOULD be correct
In a different question where the subnet mask is /27, asking for the last usable IP address in the subnet 192.168.30.0/27, option D would be correct as it would then represent the last usable address before the broadcast address of 192.168.30.31.
Option-by-option analysis
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
Why this is correct
This is correct because the .0/26 block ends at .63.
Why this is wrong here
Option B is incorrect because the broadcast address for the subnet 192.168.30.0/26 is 192.168.30.63, not 192.168.30.64. The address 192.168.30.64 is actually the first address of the next subnet (192.168.30.64/26).
★ When this WOULD be the correct answer
If the question asked for the first usable IP address of the subnet 192.168.30.0/26, then option B (192.168.30.64) would be correct, as it is the first address of the subsequent subnet after the specified range.
Why candidates choose this
Candidates may choose option B due to confusion between the broadcast address and the first address of the next subnet, especially if they misinterpret the subnetting boundaries.
Why this is wrong here
The address 192.168.30.255 is incorrect as the broadcast address for the subnet 192.168.30.0/26, which only spans IPs from 192.168.30.0 to 192.168.30.63. The broadcast address for this subnet is 192.168.30.63.
★ When this WOULD be the correct answer
If the question were about a subnet with the network address 192.168.30.0/24, then 192.168.30.255 would be the correct broadcast address, as this subnet includes all addresses from 192.168.30.0 to 192.168.30.255.
Why candidates choose this
Candidates may choose this option due to familiarity with the concept of broadcast addresses, mistakenly assuming that the highest address in any subnet is always the broadcast address without considering the subnet mask.
Why this is wrong here
Option D, 192.168.30.31, is incorrect because it represents the last usable IP address in the subnet 192.168.30.0/26, not the broadcast address. The broadcast address for this subnet is 192.168.30.63.
★ When this WOULD be the correct answer
In a different question where the subnet mask is /27, asking for the last usable IP address in the subnet 192.168.30.0/27, option D would be correct as it would then represent the last usable address before the broadcast address of 192.168.30.31.
Why candidates choose this
Candidates may choose option D due to confusion between the last usable IP address and the broadcast address, especially if they misinterpret the subnetting details or overlook the specific range of usable addresses.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Common exam traps
Remember that the broadcast address is the last address in the subnet, not the first address of the next subnet or the last usable host address.
Detailed technical explanation
Subnetting is a fundamental concept in IP networking that divides a larger network into smaller, manageable segments called subnets. Each subnet is defined by a network address and a subnet mask, which determines the size of the subnet and the range of IP addresses it contains. In this question, the subnet 192.168.30.0/26 uses a 26-bit mask, meaning the first 26 bits are fixed for the network portion, and the remaining 6 bits are available for host addresses. The /26 subnet mask corresponds to 255.255.255.192, which creates subnets with 64 IP addresses each (2^(32-26) = 64). The network address is the first IP in the block (192.168.30.0), and the broadcast address is the last IP in the block (192.168.30.63). The broadcast address is used to send packets to all hosts within that subnet. This calculation is critical for Cisco networking because devices rely on correct subnet boundaries to route and forward traffic properly. A common exam trap is confusing the broadcast address of the subnet with the broadcast address of the larger network or adjacent subnets. For example, 192.168.30.255 is the broadcast for the entire /24 network, not the /26 subnet. Misidentifying the broadcast address can cause routing and communication failures. Practically, understanding subnet boundaries ensures proper VLAN segmentation, ACL application, and IP address planning in Cisco environments.
Key takeaway
A /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely.
Real-world example
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
What to study next
Review a /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely., then practise related 200-301 questions on the same topic to reinforce the concept.
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FAQ
Network Infrastructure and Connectivity — This question tests Network Infrastructure and Connectivity — A /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely..
The correct answer is: 192.168.30.63 — A /26 subnet contains 64 addresses. In plain language, the block that starts at 192.168.30.0 runs through 192.168.30.63. The first address is the network address and the last address is the broadcast address, so the broadcast for this subnet is 192.168.30.63. This is a standard subnet-boundary calculation. Once the block size is identified, the broadcast address is simply the final address in that block.
Review a /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely., then practise related 200-301 questions on the same topic to reinforce the concept.
A /26 subnet mask divides a network into blocks of 64 IP addresses, defining the network and broadcast boundaries precisely.
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Last reviewed: May 17, 2026
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