CCNA Network Infrastructure and Connectivity Practice Question
A host with address 192.168.1.130/26 needs to identify its local subnet. Which subnet does it belong to?
⚠ Common exam trap
Be careful to calculate subnet ranges accurately and avoid assuming proximity based on the first or last octet.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
192.168.1.128/26
A /26 creates subnets in blocks of 64 addresses each. In plain language, that means the fourth octet ranges are 0–63, 64–127, 128–191, and 192–255. Since 192.168.1.130 falls within the 128–191 block, the host belongs to the 192.168.1.128/26 subnet. That is the local network boundary the host will use to decide what is on-link and what requires the default gateway. This kind of question is a very common CCNA subnetting task. The main challenge is not the arithmetic itself but recognizing the block size and locating the destination inside the correct range. Once you know a /26 moves in increments of 64, the right subnet becomes much easier to see.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
192.168.1.0/26
Why it's wrong here
The 192.168.1.0/26 subnet spans only addresses 0 through 63, with a broadcast address of 192.168.1.63. Since 130 is far beyond that broadcast address, it cannot be in this subnet. The 0/26 block includes hosts 1 through 62, but 130's binary representation has bits that fall outside the 26-bit network prefix of this block.
When this WOULD be correct
If the question asked for the first subnet in a series of subnets created from the 192.168.1.0 network with a /26 mask, then 192.168.1.0/26 would be the correct answer, as it represents the first subnet in that range.
- ✗
192.168.1.64/26
Why it's wrong here
The 192.168.1.64/26 subnet covers addresses 64 through 127, and its broadcast address is 192.168.1.127. The host 192.168.1.130 is exactly one address above that broadcast boundary, so it falls in the immediately following subnet. Thus the 64/26 block, with usable hosts 65 through 126, does not include 130.
When this WOULD be correct
If the question asked which subnet 192.168.1.130 belongs to under a different subnet mask, such as /25, then option B (192.168.1.64/26) would be correct, as it would encompass the range including 192.168.1.130.
- ✓
192.168.1.128/26
Why this is correct
The /26 prefix length corresponds to a 255.255.255.192 subnet mask, which creates address blocks of 64 addresses. Because 192.168.1.130 falls in the range 128 through 191, its network address is 192.168.1.128, making 192.168.1.128/26 the correct subnet. This is the block where 130 is a valid host, with 129 through 190 as usable addresses.
- ✗
192.168.1.192/26
Why it's wrong here
The 192.168.1.192/26 subnet starts at network address 192.168.1.192 and includes addresses 192 through 255, making its broadcast 192.168.1.255. Because 192.168.1.130 is numerically less than the network address 192, it lies in the previous subnet block. The 192/26 range is for hosts 193 through 254, so 130 cannot belong to it.
When this WOULD be correct
If the question asked which subnet a host with an address of 192.168.1.194 belongs to, then option D would be correct, as 192.168.1.194 is within the range of the 192.168.1.192/26 subnet.
Option-by-option analysis
Why each answer is right or wrong
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
✓192.168.1.128/26Correct answer▾
Why this is correct
The /26 prefix length corresponds to a 255.255.255.192 subnet mask, which creates address blocks of 64 addresses. Because 192.168.1.130 falls in the range 128 through 191, its network address is 192.168.1.128, making 192.168.1.128/26 the correct subnet. This is the block where 130 is a valid host, with 129 through 190 as usable addresses.
✗192.168.1.0/26Wrong answer — click to see why▾
Why this is wrong here
Option A is incorrect because the address 192.168.1.130 falls within the subnet range of 192.168.1.128/26, not 192.168.1.0/26, which covers addresses from 192.168.1.0 to 192.168.1.63.
★ When this WOULD be the correct answer
If the question asked for the first subnet in a series of subnets created from the 192.168.1.0 network with a /26 mask, then 192.168.1.0/26 would be the correct answer, as it represents the first subnet in that range.
Why candidates choose this
Candidates may choose this option because it represents the base address of the subnetting scheme, leading to confusion about the relationship between the base address and the specific host address.
✗192.168.1.64/26Wrong answer — click to see why▾
Why this is wrong here
Option B, 192.168.1.64/26, is incorrect because the host 192.168.1.130 falls within the subnet range of 192.168.1.128 to 192.168.1.191, not 192.168.1.64 to 192.168.1.127.
★ When this WOULD be the correct answer
If the question asked which subnet 192.168.1.130 belongs to under a different subnet mask, such as /25, then option B (192.168.1.64/26) would be correct, as it would encompass the range including 192.168.1.130.
Why candidates choose this
Candidates might choose this option due to a misunderstanding of subnet ranges, mistakenly believing that any /26 subnet could apply to the address without calculating the specific range it belongs to.
✗192.168.1.192/26Wrong answer — click to see why▾
Why this is wrong here
Option D, 192.168.1.192/26, is incorrect because the host address 192.168.1.130 falls within the subnet range of 192.168.1.128 to 192.168.1.191, making it part of the 192.168.1.128/26 subnet, not 192.168.1.192/26.
★ When this WOULD be the correct answer
If the question asked which subnet a host with an address of 192.168.1.194 belongs to, then option D would be correct, as 192.168.1.194 is within the range of the 192.168.1.192/26 subnet.
Why candidates choose this
Candidates may choose this option due to the proximity of the address ranges, leading them to mistakenly associate it with the correct subnet without fully analyzing the address range.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Visual reference
Quick reference
IPv4 Address Class Summary
| Class | First Octet Range | Default Mask | Networks | Hosts per Network |
|---|---|---|---|---|
| A | 1–126 | /8 (255.0.0.0) | 126 | 16,777,214 |
| B | 128–191 | /16 (255.255.0.0) | 16,384 | 65,534 |
| C | 192–223 | /24 (255.255.255.0) | 2,097,152 | 254 |
| D | 224–239 | N/A | Multicast groups | — |
| E | 240–255 | N/A | Reserved / experimental | — |
127.x.x.x is reserved for loopback. Modern networks use CIDR (classless) rather than classful addressing.
Go deeper
Related to this question
Learn chapter
IPv4 Addressing and Address Classes
Key term
Block size
Block size is the amount of data, measured in bytes, that a system reads or writes in a single operation, affecting storage efficiency and network performance.
Key term
Subnet
A subnet is a logical subdivision of an IP network, created by partitioning a larger network address space using subnet masks.
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Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
This 200-301 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-301 exam.