hardmultiple choiceObjective-mapped

A host address is 192.168.90.33/28. Which address is the last usable host in the subnet?

Question 1hardmultiple choice
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A host address is 192.168.90.33/28. Which address is the last usable host in the subnet?

Answer choices

Why each option matters

Good practice is not just finding the correct option. The wrong answers often show the exact trap the exam wants you to fall into.

A

Best answer

192.168.90.46

This is correct because .46 is the last usable address before the .47 broadcast in the 32-47 block.

B

Distractor review

192.168.90.47

This is wrong because .47 is the broadcast address.

C

Distractor review

192.168.90.33

This is wrong because .33 is usable, but not the last usable host.

D

Distractor review

192.168.90.48

This is wrong because .48 is in the next subnet.

Common exam trap

Common exam trap: usable hosts are not the same as total addresses

Subnetting questions often tempt you into counting all addresses. In normal IPv4 subnets, the network and broadcast addresses are not usable host addresses.

Technical deep dive

How to think about this question

Subnetting questions test whether you can identify the network, broadcast address, usable range, mask and correct subnet. Slow down enough to calculate the block size correctly.

KKey Concepts to Remember

  • CIDR notation defines the prefix length.
  • Block size helps identify subnet boundaries.
  • Network and broadcast addresses are not usable hosts in normal IPv4 subnets.
  • The required host count determines the smallest suitable subnet.

TExam Day Tips

  • Write the block size before choosing the subnet.
  • Check whether the question asks for hosts, subnets or a specific address range.
  • Do not confuse /24, /25, /26 and /27 host counts.

Related practice questions

Related 200-301 practice-question pages

Use these pages to review the topic behind this question. This is how one missed question becomes focused revision.

More questions from this exam

Keep practising from the same exam bank, or move into a focused topic page if this question exposed a weak area.

FAQ

Questions learners often ask

What does this 200-301 question test?

CIDR notation defines the prefix length.

What is the correct answer to this question?

The correct answer is: 192.168.90.46 — A /28 subnet has a block size of 16. In practical terms, the relevant ranges in the last octet are 0-15, 16-31, 32-47, and so on. Because 33 falls within the 32-47 block, the network address is 192.168.90.32 and the broadcast address is 192.168.90.47. The last usable host is therefore 192.168.90.46. This is a nice host-range question because it requires identifying the block and then reasoning to the last usable host, not just the network or broadcast address.

What should I do if I get this 200-301 question wrong?

Then try more questions from the same exam bank and focus on understanding why the wrong options are tempting.

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