hardmultiple choiceObjective-mapped

A host address is 192.168.88.66/27. Which address is the network address of the subnet?

Question 1hardmultiple choice
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A host address is 192.168.88.66/27. Which address is the network address of the subnet?

Answer choices

Why each option matters

Good practice is not just finding the correct option. The wrong answers often show the exact trap the exam wants you to fall into.

A

Distractor review

192.168.88.32

This is wrong because that is the previous /27 block.

B

Best answer

192.168.88.64

This is correct because .66 is in the 64-95 /27 subnet.

C

Distractor review

192.168.88.95

This is wrong because .95 is the broadcast address of the block, not the network address.

D

Distractor review

192.168.88.96

This is wrong because that is the start of the next /27 block.

Common exam trap

Common exam trap: answer the scenario, not the keyword

A frequent exam trap is mistaking the broadcast address or the start of the next subnet block for the network address. For example, 192.168.88.95 is the broadcast address for the 192.168.88.64/27 subnet, not the network address. Similarly, 192.168.88.96 is the start of the next subnet block. Selecting these addresses as the network address leads to incorrect subnetting and routing errors. The key is to remember that the network address is always the first address in the subnet range, which is a multiple of the block size.

Technical deep dive

How to think about this question

Subnetting is a fundamental concept in IP networking that divides a larger network into smaller, manageable subnetworks. Each subnet has a unique network address, which identifies the subnet itself, and a range of host addresses within that subnet. The subnet mask, such as /27 in this question, determines the size of each subnet and how the IP address space is divided. A /27 mask means 27 bits are fixed for the network portion, leaving 5 bits for host addresses, resulting in 32 IP addresses per subnet block. To find the network address for an IP with a /27 mask, you calculate the block size as 2^(32-27) = 32 addresses. The IP address 192.168.88.66 falls within the range 192.168.88.64 to 192.168.88.95. The network address is always the first address in the block, which is 192.168.88.64. This calculation is critical in Cisco networking for proper subnet design, routing, and access control. A common exam trap is confusing the network address with the broadcast address or the start of adjacent subnets. For example, 192.168.88.95 is the broadcast address for the 64-95 block, not the network address. Misidentifying the network address can lead to incorrect subnetting decisions and routing errors. Practically, Cisco devices use the network address to identify subnets in routing tables and ACLs, so precise calculation is essential.

KKey Concepts to Remember

  • A /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses.
  • The network address is the first IP address in the subnet block and identifies the subnet itself.
  • Host addresses fall between the network address and the broadcast address within the subnet range.
  • The broadcast address is the last IP address in the subnet block and is used to send packets to all hosts in the subnet.
  • Subnetting calculations require identifying the block size and matching the host IP to the correct subnet range.
  • Cisco routers and switches use the network address to route traffic and apply subnet-specific policies.
  • Confusing the broadcast address or adjacent subnet addresses with the network address is a common subnetting mistake.
  • Understanding subnet boundaries is essential for designing scalable and efficient IP networks in Cisco environments.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Related practice questions

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FAQ

Questions learners often ask

What does this 200-301 question test?

A /27 subnet mask divides an IP network into blocks of 32 addresses, including network and broadcast addresses.

What is the correct answer to this question?

The correct answer is: 192.168.88.64 — A /27 subnet has a block size of 32. In practical terms, the fourth-octet ranges are 0-31, 32-63, 64-95, and so on. Because 66 falls within the 64-95 block, the network address is 192.168.88.64. This is a classic subnet-boundary calculation. The key step is identifying the correct block first.

What should I do if I get this 200-301 question wrong?

Then try more questions from the same exam bank and focus on understanding why the wrong options are tempting.

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