This 200-301 practice question tests your understanding of network infrastructure and connectivity. Match the stated requirement to the specific cloud service, access model, or configuration option — many options are valid in isolation but not for this scenario. A key principle to apply: a /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses.. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A host address is 192.168.1.14/29. Which address is the broadcast address for that host’s subnet?
192.168.1.7
Why wrong: This is wrong because .7 is the broadcast of the 0–7 /29 block, not the block containing .14.
192.168.1.14
Why wrong: This is wrong because .14 is the host address, not the broadcast address.
192.168.1.15
This is correct because the host is in the 8–15 /29 block, whose broadcast is .15.
192.168.1.16
Why wrong: This is wrong because .16 is the start of the next /29 block.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
192.168.1.15
A /29 uses blocks of 8 addresses. In plain language, the subnets in the last octet move in increments of 8: 0–7, 8–15, 16–23, and so on. Since the host address ends in 14, it belongs to the 8–15 block. In that block, the last address is the broadcast address, so the broadcast is 192.168.1.15. This is a classic subnetting pattern because it requires you to place the host inside the correct block and then identify the last address in that block rather than guessing based on the host value itself.
Key principle: A /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
192.168.1.7
Why it's wrong here
This is wrong because .7 is the broadcast of the 0–7 /29 block, not the block containing .14.
When this WOULD be correct
If the question asked for the broadcast address of the subnet 192.168.1.0/29 instead, then 192.168.1.7 would be the correct answer, as it would be the highest address in that specific subnet range.
192.168.1.14
Why it's wrong here
This is wrong because .14 is the host address, not the broadcast address.
When this WOULD be correct
In a different question setup where the question asks for the host address of a specific device within a subnet, and the subnet is defined as 192.168.1.14/29, option B could be correct if the question specifically inquires about the address assigned to that device.
192.168.1.15
Why this is correct
This is correct because the host is in the 8–15 /29 block, whose broadcast is .15.
Related concept
A /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses.
192.168.1.16
Why it's wrong here
This is wrong because .16 is the start of the next /29 block.
When this WOULD be correct
In a different scenario where the subnet mask is changed to /28, the subnet would range from 192.168.1.0 to 192.168.1.15. In this case, if the host address was 192.168.1.14, the broadcast address would indeed be 192.168.1.16.
Option-by-option analysis
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
Why this is correct
This is correct because the host is in the 8–15 /29 block, whose broadcast is .15.
Why this is wrong here
192.168.1.7 is the broadcast address for the /29 block 0–7, which does not contain host .14. The host .14 is in the block 8–15, so its broadcast is .15.
★ When this WOULD be the correct answer
If the question asked for the broadcast address of the subnet 192.168.1.0/29 instead, then 192.168.1.7 would be the correct answer, as it would be the highest address in that specific subnet range.
Why candidates choose this
Students often miscalculate the block size or confuse the network address with the broadcast address. They might think .7 is the broadcast because it is the last address in the first block, but they forget to check which block contains .14.
Why this is wrong here
192.168.1.14 is the host address itself, not the broadcast address. The broadcast address is always the last address in the subnet, which is .15 for the block 8–15.
★ When this WOULD be the correct answer
In a different question setup where the question asks for the host address of a specific device within a subnet, and the subnet is defined as 192.168.1.14/29, option B could be correct if the question specifically inquires about the address assigned to that device.
Why candidates choose this
Some students think the broadcast address is the same as the host address or that the host address itself can be used for broadcasting. They may not understand that the broadcast address is a special reserved address.
Why this is wrong here
192.168.1.16 is the network address of the next /29 block (16–23), not the broadcast address for the block containing .14. The broadcast address must be the last address in the same block as the host.
★ When this WOULD be the correct answer
In a different scenario where the subnet mask is changed to /28, the subnet would range from 192.168.1.0 to 192.168.1.15. In this case, if the host address was 192.168.1.14, the broadcast address would indeed be 192.168.1.16.
Why candidates choose this
A common mistake is to add the block size (8) to the host address and assume that is the broadcast. For example, 14 + 8 = 22, but .16 is not the broadcast; it is the next network address. Students may also confuse broadcast with network address.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Common exam traps
Be careful not to confuse the network address or the next subnet's network address with the broadcast address.
Detailed technical explanation
Subnetting divides an IP network into smaller logical segments called subnets, each with its own range of IP addresses. A /29 subnet mask means the subnet uses 29 bits for the network portion and 3 bits for host addresses, resulting in 8 total IP addresses per subnet block. These 8 addresses include one network address, six usable host addresses, and one broadcast address. The subnet blocks increment by 8 in the last octet, such as 0–7, 8–15, 16–23, etc., which helps identify the subnet boundaries. To determine the broadcast address for a host IP like 192.168.1.14/29, you first identify which subnet block the host belongs to by checking the last octet and matching it to the subnet increments. Since 14 falls within the 8–15 range, the subnet is 192.168.1.8/29. The broadcast address is always the last IP in the subnet block, which is 192.168.1.15 in this case. This address is used to send packets to all hosts within that subnet. A common exam trap is confusing the broadcast address with the host address or the network address of adjacent subnets. For example, mistaking 192.168.1.7 as the broadcast address for the subnet containing .14 is incorrect because .7 belongs to the 0–7 block, not the 8–15 block. Understanding subnet increments and correctly identifying subnet boundaries prevents this mistake and ensures accurate subnetting in Cisco environments.
Key takeaway
A /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses.
Real-world example
A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.
What to study next
Review a /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
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FAQ
Network Infrastructure and Connectivity — This question tests Network Infrastructure and Connectivity — A /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses..
The correct answer is: 192.168.1.15 — A /29 uses blocks of 8 addresses. In plain language, the subnets in the last octet move in increments of 8: 0–7, 8–15, 16–23, and so on. Since the host address ends in 14, it belongs to the 8–15 block. In that block, the last address is the broadcast address, so the broadcast is 192.168.1.15. This is a classic subnetting pattern because it requires you to place the host inside the correct block and then identify the last address in that block rather than guessing based on the host value itself.
Review a /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
A /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses.
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Last reviewed: May 17, 2026
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