Question 1hardmultiple choice
Full question →hardmultiple choiceObjective-mapped
A host address is 192.168.1.14/29. Which address is the broadcast address for that host’s subnet?
Answer choices
Why each option matters
Good practice is not just finding the correct option. The wrong answers often show the exact trap the exam wants you to fall into.
A
Distractor review
192.168.1.7
This is wrong because .7 is the broadcast of the 0–7 /29 block, not the block containing .14.
B
Distractor review
192.168.1.14
This is wrong because .14 is the host address, not the broadcast address.
C
Best answer
192.168.1.15
This is correct because the host is in the 8–15 /29 block, whose broadcast is .15.
D
Distractor review
192.168.1.16
This is wrong because .16 is the start of the next /29 block.
Common exam trap
Common exam trap: answer the scenario, not the keyword
A frequent exam trap is selecting an IP address that appears numerically close to the host IP but belongs to a different subnet block. For example, choosing 192.168.1.7 as the broadcast address for 192.168.1.14/29 is incorrect because .7 is the broadcast for the 0–7 block, not the 8–15 block where .14 resides. This mistake happens when candidates do not carefully calculate subnet increments or confuse the broadcast address with the host address itself. Avoid this trap by always identifying the correct subnet block before determining the broadcast address.
Technical deep dive
How to think about this question
Subnetting divides an IP network into smaller logical segments called subnets, each with its own range of IP addresses. A /29 subnet mask means the subnet uses 29 bits for the network portion and 3 bits for host addresses, resulting in 8 total IP addresses per subnet block. These 8 addresses include one network address, six usable host addresses, and one broadcast address. The subnet blocks increment by 8 in the last octet, such as 0–7, 8–15, 16–23, etc., which helps identify the subnet boundaries. To determine the broadcast address for a host IP like 192.168.1.14/29, you first identify which subnet block the host belongs to by checking the last octet and matching it to the subnet increments. Since 14 falls within the 8–15 range, the subnet is 192.168.1.8/29. The broadcast address is always the last IP in the subnet block, which is 192.168.1.15 in this case. This address is used to send packets to all hosts within that subnet. A common exam trap is confusing the broadcast address with the host address or the network address of adjacent subnets. For example, mistaking 192.168.1.7 as the broadcast address for the subnet containing .14 is incorrect because .7 belongs to the 0–7 block, not the 8–15 block. Understanding subnet increments and correctly identifying subnet boundaries prevents this mistake and ensures accurate subnetting in Cisco environments.
KKey Concepts to Remember
- A /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses.
- Subnet blocks increment by 8 in the last octet, such as 0–7, 8–15, 16–23, which defines subnet boundaries.
- The broadcast address is always the highest IP address in the subnet block and is used to send packets to all hosts in that subnet.
- To find the broadcast address, first identify the subnet block containing the host IP by matching the last octet to subnet increments.
- Confusing broadcast addresses from adjacent subnet blocks is a common mistake that leads to incorrect subnetting answers.
- The host IP address itself can never be the broadcast address; they serve distinct roles in subnet communication.
- Cisco devices use subnet masks to determine network and broadcast addresses, which is critical for routing and ACL configurations.
- Correct subnetting ensures proper network segmentation, efficient IP address usage, and accurate packet delivery within Cisco networks.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
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More questions from this exam
Keep practising from the same exam bank, or move into a focused topic page if this question exposed a weak area.
Question 1
A router learns the same prefix from both OSPF and EIGRP. Which route is installed by default?
Question 2
A router shows this output: R1#show ip ospf neighbor Neighbor ID Pri State Dead Time Address Interface 10.1.1.2 1 FULL/DR 00:00:34 192.168.12.2 GigabitEthernet0/0 10.1.1.3 1 2WAY/DROTHER 00:00:39 192.168.12.3 GigabitEthernet0/0 Which statement is correct?
Question 3
What is the OSPF metric called?
Question 4
A non-root switch has two uplinks toward the root bridge. One path has a lower total STP cost than the other. What role will the lower-cost uplink have?
Question 5
A router interface applies this ACL inbound: 10 deny tcp any any eq 80 20 permit ip any any A user reports that web browsing to a server by IP address fails, but ping works. Which statement best explains the behavior?
Question 6
A router learns route 198.51.100.0/24 from OSPF with AD 110 and also has a static route to the same prefix configured with AD 150. Which route is installed?
FAQ
Questions learners often ask
What does this 200-301 question test?
A /29 subnet mask divides an IP network into blocks of 8 addresses, including network, broadcast, and usable host addresses.
What is the correct answer to this question?
The correct answer is: 192.168.1.15 — A /29 uses blocks of 8 addresses. In plain language, the subnets in the last octet move in increments of 8: 0–7, 8–15, 16–23, and so on. Since the host address ends in 14, it belongs to the 8–15 block. In that block, the last address is the broadcast address, so the broadcast is 192.168.1.15. This is a classic subnetting pattern because it requires you to place the host inside the correct block and then identify the last address in that block rather than guessing based on the host value itself.
What should I do if I get this 200-301 question wrong?
Then try more questions from the same exam bank and focus on understanding why the wrong options are tempting.
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