This 200-301 practice question tests your understanding of network infrastructure and connectivity. Match the stated requirement to the specific cloud service, access model, or configuration option — many options are valid in isolation but not for this scenario. A key principle to apply: a /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses.. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A host address is 172.22.14.99/27. Which address is the broadcast address of the subnet?
172.22.14.95
Why wrong: This is wrong because .95 is the broadcast address of the previous /27 block.
172.22.14.127
This is correct because .99 belongs to the 96-127 /27 subnet.
172.22.14.96
Why wrong: This is wrong because .96 is the network address of the subnet.
172.22.14.128
Why wrong: This is wrong because .128 starts the next subnet.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
172.22.14.127
A /27 subnet has a block size of 32. In practical terms, the relevant blocks are 0-31, 32-63, 64-95, 96-127, and so on. Because 99 falls within the 96-127 block, the broadcast address is the last address in that block: 172.22.14.127. This is a classic subnet-boundary question and remains important because addressing precision appears throughout the CCNA blueprint.
Key principle: A /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
172.22.14.95
Why it's wrong here
This is wrong because .95 is the broadcast address of the previous /27 block.
When this WOULD be correct
In a different question where the subnet mask was /26 and the host address was 172.22.14.99, option A (172.22.14.95) could be the broadcast address for that subnet. This would occur if the address range was defined such that 172.22.14.64/26 had 172.22.14.95 as its broadcast address.
172.22.14.127
Why this is correct
This is correct because .99 belongs to the 96-127 /27 subnet.
Related concept
A /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses.
172.22.14.96
Why it's wrong here
This is wrong because .96 is the network address of the subnet.
When this WOULD be correct
In a different scenario where the subnet mask is changed to /26, the address 172.22.14.96 could be the broadcast address for the subnet 172.22.14.64/26. In this case, the range would include addresses from 172.22.14.65 to 172.22.14.126, making 172.22.14.126 the broadcast address.
172.22.14.128
Why it's wrong here
This is wrong because .128 starts the next subnet.
When this WOULD be correct
In a different question where the subnet mask is /25, the broadcast address for the subnet containing 172.22.14.128 would be 172.22.14.255. In this scenario, option D would be the correct answer as it would represent the broadcast address for that specific subnet.
Option-by-option analysis
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
Why this is correct
This is correct because .99 belongs to the 96-127 /27 subnet.
Why this is wrong here
Option A is incorrect because the broadcast address for the subnet 172.22.14.99/27 is 172.22.14.127, not 172.22.14.95. The /27 subnet mask indicates that the last 5 bits are for host addresses, allowing for a range of addresses that ends at 172.22.14.127.
★ When this WOULD be the correct answer
In a different question where the subnet mask was /26 and the host address was 172.22.14.99, option A (172.22.14.95) could be the broadcast address for that subnet. This would occur if the address range was defined such that 172.22.14.64/26 had 172.22.14.95 as its broadcast address.
Why candidates choose this
Candidates may choose option A due to a miscalculation of the subnet range, mistakenly believing that the lower end of the host address range is the broadcast address. This can happen if they confuse the calculation of usable addresses in a subnet.
Why this is wrong here
Option C (172.22.14.96) is incorrect because it falls within the usable host range of the subnet and is not the broadcast address. The broadcast address for the subnet 172.22.14.96/27 is actually 172.22.14.127.
★ When this WOULD be the correct answer
In a different scenario where the subnet mask is changed to /26, the address 172.22.14.96 could be the broadcast address for the subnet 172.22.14.64/26. In this case, the range would include addresses from 172.22.14.65 to 172.22.14.126, making 172.22.14.126 the broadcast address.
Why candidates choose this
Candidates may choose this option due to confusion between the subnet address and the broadcast address, as they might miscalculate the range of usable addresses and mistakenly identify 172.22.14.96 as a boundary address.
Why this is wrong here
Option D, 172.22.14.128, is incorrect because it does not fall within the subnet defined by 172.22.14.99/27, which has a valid range of 172.22.14.96 to 172.22.14.127. The broadcast address for this subnet is 172.22.14.127.
★ When this WOULD be the correct answer
In a different question where the subnet mask is /25, the broadcast address for the subnet containing 172.22.14.128 would be 172.22.14.255. In this scenario, option D would be the correct answer as it would represent the broadcast address for that specific subnet.
Why candidates choose this
Candidates may be tempted by option D because it is a higher address within the same octet, leading them to mistakenly associate it with the broadcast address due to common subnetting patterns.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Common exam traps
Be careful not to confuse network addresses with broadcast addresses, and ensure you are calculating the correct subnet range.
Detailed technical explanation
Subnetting divides an IP network into smaller, manageable segments called subnets, each with its own network address, broadcast address, and host range. A /27 subnet mask corresponds to 255.255.255.224, which means 27 bits are fixed for the network portion and 5 bits are left for host addressing. This results in 32 IP addresses per subnet block, including the network and broadcast addresses. To find the broadcast address for a given host IP and subnet mask, you identify the subnet block the IP belongs to by calculating the block size (32 for /27) and determining the range of addresses within that block. For 172.22.14.99/27, the subnet block ranges from 172.22.14.96 to 172.22.14.127. The broadcast address is always the last IP in the subnet block, which is 172.22.14.127 in this case. A common exam trap is confusing the broadcast address with the network address or the broadcast address of an adjacent subnet. For example, 172.22.14.95 is the broadcast address of the previous subnet block (64-95), not the current one. Understanding the block boundaries and correctly calculating the broadcast address prevents such mistakes and ensures accurate subnetting in Cisco network configurations.
Key takeaway
A /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses.
Real-world example
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
What to study next
Review a /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
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FAQ
Network Infrastructure and Connectivity — This question tests Network Infrastructure and Connectivity — A /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses..
The correct answer is: 172.22.14.127 — A /27 subnet has a block size of 32. In practical terms, the relevant blocks are 0-31, 32-63, 64-95, 96-127, and so on. Because 99 falls within the 96-127 block, the broadcast address is the last address in that block: 172.22.14.127. This is a classic subnet-boundary question and remains important because addressing precision appears throughout the CCNA blueprint.
Review a /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
A /27 subnet mask creates subnets with 32 IP addresses, including network and broadcast addresses.
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Last reviewed: May 17, 2026
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