This 200-301 practice question tests your understanding of network infrastructure and connectivity. Match the stated requirement to the specific cloud service, access model, or configuration option — many options are valid in isolation but not for this scenario. A key principle to apply: a /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses.. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A host address is 10.55.8.117/29. Which address is the network address of the subnet?
10.55.8.112
This is correct because .117 belongs to the 112-119 /29 block.
10.55.8.119
Why wrong: This is wrong because .119 is the broadcast address of the subnet.
10.55.8.120
Why wrong: This is wrong because .120 begins the next /29 block.
10.55.8.116
Why wrong: This is wrong because .116 is a usable host in the subnet, not the network address.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
10.55.8.112
A /29 subnet has a block size of 8. In practical terms, the relevant last-octet blocks are 112-119 for this host. That means the network address is 10.55.8.112. Once you identify the correct block, the first address in the block is the network address. This is a useful addressing-boundary question because it checks careful block calculation, not memorized guesses.
Key principle: A /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
10.55.8.112
Why this is correct
This is correct because .117 belongs to the 112-119 /29 block.
Related concept
A /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses.
10.55.8.119
Why it's wrong here
This is wrong because .119 is the broadcast address of the subnet.
When this WOULD be correct
In a different question where the subnet mask is /29 and the host address is 10.55.8.119, asking for the broadcast address of the subnet, option B would be correct as it represents the last usable address before the broadcast address of 10.55.8.127.
10.55.8.120
Why it's wrong here
This is wrong because .120 begins the next /29 block.
When this WOULD be correct
If the question were to ask for the broadcast address of the subnet instead of the network address, 10.55.8.120 could be correct, as it is the last address in the subnet range for 10.55.8.112/29.
10.55.8.116
Why it's wrong here
This is wrong because .116 is a usable host in the subnet, not the network address.
When this WOULD be correct
In a different question setup where the subnet mask is /28 and the host address is 10.55.8.116, option D would be the correct answer as it would then represent the network address for that subnet, which includes addresses from 10.55.8.112 to 10.55.8.127.
Option-by-option analysis
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
Why this is correct
This is correct because .117 belongs to the 112-119 /29 block.
Why this is wrong here
10.55.8.119 is the broadcast address for the subnet 10.55.8.112/29, not the network address. The broadcast address is the last address in the block (112+8-1=119) and is used to send traffic to all hosts in the subnet.
★ When this WOULD be the correct answer
In a different question where the subnet mask is /29 and the host address is 10.55.8.119, asking for the broadcast address of the subnet, option B would be correct as it represents the last usable address before the broadcast address of 10.55.8.127.
Why candidates choose this
Students often confuse the broadcast address with the network address because both are special addresses within the subnet. The broadcast address is the highest address, while the network address is the lowest.
Why this is wrong here
10.55.8.120 is the network address of the next /29 subnet (120-127), not the current one. The current subnet ends at 119, so 120 belongs to a different subnet.
★ When this WOULD be the correct answer
If the question were to ask for the broadcast address of the subnet instead of the network address, 10.55.8.120 could be correct, as it is the last address in the subnet range for 10.55.8.112/29.
Why candidates choose this
A common mistake is to assume the network address is the next multiple of 8 after the host address, but the correct network address is the multiple of 8 that is less than or equal to the host address.
Why this is wrong here
10.55.8.116 is a valid host address within the subnet 10.55.8.112/29 (usable range: 113-118). It is not the network address, which must be the first address (112).
★ When this WOULD be the correct answer
In a different question setup where the subnet mask is /28 and the host address is 10.55.8.116, option D would be the correct answer as it would then represent the network address for that subnet, which includes addresses from 10.55.8.112 to 10.55.8.127.
Why candidates choose this
Students may think the network address is close to the host address, such as rounding down to the nearest even number, but the correct method is to find the block boundary using the subnet mask.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Common exam traps
Be careful not to confuse the network address with the first usable host or the broadcast address.
Detailed technical explanation
Subnetting is a fundamental concept in IP networking that divides a larger network into smaller, manageable subnetworks. Each subnet has a network address, a range of usable host addresses, and a broadcast address. The subnet mask determines the size of each subnet and the number of hosts it can support. In this question, the /29 prefix indicates a subnet mask of 255.255.255.248, which means each subnet contains 8 IP addresses (2^3 = 8), including the network and broadcast addresses. To find the network address for a given host IP and subnet mask, you calculate the block size based on the subnet mask and then identify the range in which the host IP falls. For a /29 subnet, the block size is 8. The host IP 10.55.8.117 falls within the block starting at 10.55.8.112 and ending at 10.55.8.119. The first address in this block, 10.55.8.112, is the network address, and the last address, 10.55.8.119, is the broadcast address. A common exam trap is confusing the network address with usable host addresses or the broadcast address. For example, 10.55.8.116 is a usable host address, not the network address, and 10.55.8.119 is the broadcast address, not a network address. Understanding the block size and correctly identifying the subnet boundaries is critical in Cisco CCNA subnetting questions and practical networking scenarios.
Key takeaway
A /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses.
Real-world example
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
What to study next
Review a /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
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FAQ
Network Infrastructure and Connectivity — This question tests Network Infrastructure and Connectivity — A /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses..
The correct answer is: 10.55.8.112 — A /29 subnet has a block size of 8. In practical terms, the relevant last-octet blocks are 112-119 for this host. That means the network address is 10.55.8.112. Once you identify the correct block, the first address in the block is the network address. This is a useful addressing-boundary question because it checks careful block calculation, not memorized guesses.
Review a /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
A /29 subnet mask corresponds to 255.255.255.248, which creates subnets with 8 IP addresses each, including network and broadcast addresses.
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Last reviewed: May 17, 2026
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