hardmultiple choiceObjective-mapped

A host address is 10.100.12.94/26. Which address is the broadcast address for that subnet?

Question 1hardmultiple choice
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A host address is 10.100.12.94/26. Which address is the broadcast address for that subnet?

Answer choices

Why each option matters

Good practice is not just finding the correct option. The wrong answers often show the exact trap the exam wants you to fall into.

A

Distractor review

10.100.12.63

This is wrong because .63 is the broadcast address of the previous /26 block.

B

Best answer

10.100.12.127

This is correct because .94 is in the 64-127 /26 range.

C

Distractor review

10.100.12.64

This is wrong because .64 is the network address of that subnet.

D

Distractor review

10.100.12.128

This is wrong because .128 starts the next subnet.

Common exam trap

Common exam trap: answer the scenario, not the keyword

A frequent exam trap is selecting the broadcast address of the wrong subnet block. Candidates often mistake 10.100.12.63 as the broadcast address because it ends with .63, which looks similar to the /26 block size. However, .63 is actually the broadcast address of the previous subnet (0-63). Another trap is confusing the network address (10.100.12.64) with the broadcast address. Misidentifying these boundaries leads to incorrect subnetting answers and can cause routing and communication issues in real networks.

Technical deep dive

How to think about this question

Subnetting is a fundamental concept in IP networking that divides a larger network into smaller, manageable subnetworks. A /26 subnet mask means the first 26 bits are fixed for the network portion, leaving 6 bits for host addresses. This results in 64 IP addresses per subnet, including network and broadcast addresses. The subnet mask 255.255.255.192 corresponds to /26, which splits the IP address range into blocks of 64 addresses. To find the broadcast address for a given host IP and subnet mask, you first identify the subnet block the IP belongs to by calculating the block size (256 minus the last octet of the subnet mask). For /26, the block size is 64, so the subnets are 0-63, 64-127, 128-191, and 192-255. Since 10.100.12.94 falls within 64-127, the broadcast address is the last address in that block, 10.100.12.127. A common exam trap is confusing the broadcast address with the network address or the broadcast address of an adjacent subnet. For example, 10.100.12.63 is the broadcast for the previous subnet (0-63), and 10.100.12.64 is the network address of the current subnet. Understanding the block boundaries and correctly identifying the subnet range prevents this mistake. In practical Cisco networking, accurate broadcast address calculation is essential for proper subnet communication and avoiding IP conflicts.

KKey Concepts to Remember

  • A /26 subnet mask divides the IP address space into blocks of 64 addresses, including network and broadcast addresses.
  • The broadcast address is the highest IP address in the subnet block and is used to send packets to all hosts within that subnet.
  • To find the subnet block, subtract the last octet of the subnet mask from 256 to determine the block size for the fourth octet.
  • The network address is the first IP address in the subnet block and cannot be assigned to hosts.
  • Hosts with IP addresses within a subnet range share the same network and broadcast addresses for communication.
  • Incorrectly identifying the broadcast address as the network address or an adjacent subnet’s broadcast address is a common subnetting error.
  • Cisco devices use subnet masks to determine the network and broadcast boundaries for routing and forwarding decisions.
  • Understanding subnet boundaries is critical for configuring IP addressing and avoiding address conflicts in Cisco networks.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Related practice questions

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FAQ

Questions learners often ask

What does this 200-301 question test?

A /26 subnet mask divides the IP address space into blocks of 64 addresses, including network and broadcast addresses.

What is the correct answer to this question?

The correct answer is: 10.100.12.127 — A /26 subnet has a block size of 64. In practical terms, the fourth-octet blocks are 0-63, 64-127, 128-191, and 192-255. Because 94 falls into the 64-127 block, the broadcast address is 10.100.12.127. This is a boundary-calculation question that checks whether you can identify the correct /26 range first.

What should I do if I get this 200-301 question wrong?

Then try more questions from the same exam bank and focus on understanding why the wrong options are tempting.

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