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Network Infrastructure and ConnectivityhardMultiple ChoiceObjective-mapped

CCNA Network Infrastructure and Connectivity Practice Question

A host address is 10.100.12.94/26. Which address is the broadcast address for that subnet?

⚠ Common exam trap

Be careful not to confuse host addresses or network addresses with the broadcast address. Remember, the broadcast address is the last address in the subnet range.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

10.100.12.127

A /26 subnet has a block size of 64, so the fourth-octet ranges are 0–63, 64–127, 128–191, and 192–255. The host address 10.100.12.94 lies in the 64–127 range, making the broadcast address the last address in that range: 10.100.12.127. Option A (10.100.12.63) is the broadcast of the previous subnet (0–63). Option C (10.100.12.64) is the network address of the subnet containing the host. Option D (10.100.12.128) is the network address of the next subnet (128–191).

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • 10.100.12.63

    Why it's wrong here

    This is wrong because .63 is the broadcast address of the previous /26 block.

    When this WOULD be correct

    In a question where the subnet mask is /26 and the network address is 10.100.12.0, if the question mistakenly states that the subnet ends at 10.100.12.63, then 10.100.12.63 would be the correct broadcast address for that defined range.

  • 10.100.12.127

    Why this is correct

    This is correct because .94 is in the 64-127 /26 range.

  • 10.100.12.64

    Why it's wrong here

    This is wrong because .64 is the network address of that subnet.

    When this WOULD be correct

    In a different question setup where the subnet mask is /26 and the network address is 10.100.12.64, option C would be the correct answer if the question asked for the first usable host address instead of the broadcast address.

  • 10.100.12.128

    Why it's wrong here

    This is wrong because .128 starts the next subnet.

    When this WOULD be correct

    If the question were to ask for the broadcast address of a subnet defined by 10.100.12.128/26, then option D would be correct, as the broadcast address for that subnet would be 10.100.12.191.

Option-by-option analysis

Why each answer is right or wrong

Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.

10.100.12.127Correct answer

Why this is correct

This is correct because .94 is in the 64-127 /26 range.

10.100.12.63Wrong answer — click to see why

Why this is wrong here

The address 10.100.12.63 is incorrect as the broadcast address for the subnet 10.100.12.0/26, which actually has a range from 10.100.12.0 to 10.100.12.63. The correct broadcast address for the subnet is 10.100.12.127.

★ When this WOULD be the correct answer

In a question where the subnet mask is /26 and the network address is 10.100.12.0, if the question mistakenly states that the subnet ends at 10.100.12.63, then 10.100.12.63 would be the correct broadcast address for that defined range.

Why candidates choose this

Candidates may choose this option due to a misunderstanding of subnetting, where they incorrectly calculate the broadcast address by only considering the last octet and not accounting for the subnet mask properly.

10.100.12.64Wrong answer — click to see why

Why this is wrong here

Option C (10.100.12.64) is incorrect because it is the first usable host address in the subnet 10.100.12.64/26, not the broadcast address. The broadcast address for this subnet is 10.100.12.127.

★ When this WOULD be the correct answer

In a different question setup where the subnet mask is /26 and the network address is 10.100.12.64, option C would be the correct answer if the question asked for the first usable host address instead of the broadcast address.

Why candidates choose this

Candidates might choose option C due to confusion between the broadcast address and the first usable address in a subnet, especially if they miscalculate the range of addresses available in a /26 subnet.

10.100.12.128Wrong answer — click to see why

Why this is wrong here

Option D (10.100.12.128) is incorrect because it does not fall within the range of addresses for the subnet defined by 10.100.12.94/26, which spans from 10.100.12.64 to 10.100.12.127.

★ When this WOULD be the correct answer

If the question were to ask for the broadcast address of a subnet defined by 10.100.12.128/26, then option D would be correct, as the broadcast address for that subnet would be 10.100.12.191.

Why candidates choose this

Candidates may be tempted by option D because it is a common mistake to miscalculate subnet boundaries, especially when dealing with larger subnets or when they misinterpret the CIDR notation.

Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 200-301 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-301 exam.