The answer is that the case function fails with CIDR notation because it cannot compare IP addresses to CIDR ranges, treating the notation as a literal string instead. The case function evaluates conditions sequentially, and since no IP matches the string '10.0.0.0/8', the always-true condition '1=1' assigns all remaining events the value 'external'. On the Splunk Core Certified User SPLK-1002 exam, this tests your understanding that eval functions like case work on exact field values, not subnet logic—a common trap where candidates assume CIDR matching works automatically. To handle IP ranges, you must use the cidrmatch function instead. Remember the mnemonic: “Case for exact, cidrmatch for the mask.”
SPLK-1002 Basic Searching and Transforming Commands Practice Question
This SPLK-1002 practice question tests your understanding of basic searching and transforming commands. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The 'case' function cannot compare IP addresses to CIDR ranges
The 'case' function evaluates conditions in order. The second condition '1=1' is always true, so any IP not matching '10.0.0.0/8' gets 'external'. However, the 'case' function does not support CIDR matching; it treats '10.0.0.0/8' as a literal string. So no IP matches the first condition, and all get 'external'.
Key principle: Count usable hosts — not total addresses — and remember that the network and broadcast addresses are not available to hosts in standard IPv4 subnets.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
The 'src_ip' field is not extracted
Why it's wrong here
It is extracted.
✗
The default condition should be 'true()' instead of '1=1'
Common exam trap: usable hosts are not the same as total addresses
Subnetting questions often tempt you into counting all addresses. In normal IPv4 subnets, the network and broadcast addresses are not usable host addresses.
Detailed technical explanation
How to think about this question
Subnetting questions test whether you can identify the network, broadcast address, usable range, mask and correct subnet. Slow down enough to calculate the block size correctly.
KKey Concepts to Remember
CIDR notation defines the prefix length.
Block size helps identify subnet boundaries.
Network and broadcast addresses are not usable hosts in normal IPv4 subnets.
The required host count determines the smallest suitable subnet.
TExam Day Tips
→Write the block size before choosing the subnet.
→Check whether the question asks for hosts, subnets or a specific address range.
→Do not confuse /24, /25, /26 and /27 host counts.
Key takeaway
Count usable hosts — not total addresses — and remember that the network and broadcast addresses are not available to hosts in standard IPv4 subnets.
Real-world example
How this comes up in practice
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
What to study next
Got this wrong? Here's your next step.
Review block sizes, usable host formulas (2^n − 2), and how to find network and broadcast addresses for /24 through /30. Then practise related SPLK-1002 subnetting questions on CIDR, address ranges, and subnet selection.
Basic Searching and Transforming Commands — This question tests Basic Searching and Transforming Commands — CIDR notation defines the prefix length..
What is the correct answer to this question?
The correct answer is: The 'case' function cannot compare IP addresses to CIDR ranges — The 'case' function evaluates conditions in order. The second condition '1=1' is always true, so any IP not matching '10.0.0.0/8' gets 'external'. However, the 'case' function does not support CIDR matching; it treats '10.0.0.0/8' as a literal string. So no IP matches the first condition, and all get 'external'.
What should I do if I get this SPLK-1002 question wrong?
Review block sizes, usable host formulas (2^n − 2), and how to find network and broadcast addresses for /24 through /30. Then practise related SPLK-1002 subnetting questions on CIDR, address ranges, and subnet selection.
What is the key concept behind this question?
CIDR notation defines the prefix length.
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Question Discussion
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