The correct answer is that version comparison will not be numeric, giving incorrect results because the `where` clause performs lexicographic (string) comparison on the `version` field. When Splunk evaluates strings like '2.0' and '10.0' character by character, '2' is greater than '1', so '2.0' is considered larger than '10.0'—a classic failure of string vs numeric version comparison. On the SPLK-1002 exam, this question tests your understanding of data types in lookups and how Splunk’s comparison operators behave; the common trap is assuming that fields containing numbers are automatically treated as numeric. To avoid this, always check field types in the lookup file or use `tonumber(version)` in your search to force numeric comparison. Memory tip: think of string comparison as alphabetizing—'10' comes before '2' because '1' < '2', but numerically it’s the opposite.
SPLK-1002 Using Fields and Lookups Practice Question
This SPLK-1002 practice question tests your understanding of using fields and lookups. The scenario asks you to isolate a root cause — eliminate options that address a different problem before choosing. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Exhibit
Refer to the exhibit.
| inputlookup app_versions.csv
| where version > "2.0"
| table app version
Refer to the exhibit. The lookup file app_versions.csv contains fields 'app' and 'version'. The version values are strings like '1.5', '2.0', '2.1'. What is the issue with this search?
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Version comparison will not be numeric, giving incorrect results
The issue is that the `where` clause performs lexicographic (string) comparison on the `version` field because the values in the lookup file are stored as strings (e.g., '1.5', '2.0', '2.1'). Since string comparison evaluates character by character, a version like '2.0' would be considered greater than '10.0' because '2' > '1' as a character, leading to incorrect filtering results. To compare versions numerically, you must convert the field to a numeric type using functions like `tonumber()` or parse the version string into comparable components.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✓
Version comparison will not be numeric, giving incorrect results
Why this is correct
String comparison fails for version numbers.
Related concept
Read the scenario before looking for a memorised answer.
✗
where cannot be used with string comparisons
Why it's wrong here
where works with strings.
✗
inputlookup is not a valid command
Why it's wrong here
inputlookup is valid.
✗
table should be replaced with fields
Why it's wrong here
table is fine.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Splunk often tests the misconception that `where` can automatically handle numeric comparisons for fields that look like numbers but are stored as strings, leading candidates to overlook the need for explicit type conversion.
Detailed technical explanation
How to think about this question
Under the hood, Splunk's `where` command uses the same comparison operators as the search language, which default to string comparison for string fields. For version strings like '1.5', '2.0', '2.1', lexicographic ordering does not align with semantic versioning; for example, '9.9' would be considered greater than '10.0' because '9' > '1'. A robust solution involves splitting the version into major and minor parts using `eval` and `split()`, then comparing numeric values, or using `tonumber()` on the entire string if the format is consistently numeric (e.g., '1.5' becomes 1.5 as a float). In real-world scenarios, this issue commonly arises when comparing software versions, IP addresses, or any dotted-decimal strings where numeric ordering is expected.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the SPLK-1002 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Using Fields and Lookups — This question tests Using Fields and Lookups — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: Version comparison will not be numeric, giving incorrect results — The issue is that the `where` clause performs lexicographic (string) comparison on the `version` field because the values in the lookup file are stored as strings (e.g., '1.5', '2.0', '2.1'). Since string comparison evaluates character by character, a version like '2.0' would be considered greater than '10.0' because '2' > '1' as a character, leading to incorrect filtering results. To compare versions numerically, you must convert the field to a numeric type using functions like `tonumber()` or parse the version string into comparable components.
What should I do if I get this SPLK-1002 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Question Discussion
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