The answer is `index=* earliest=-1h | stats count by host`. This is the most efficient search because it applies the time filter at the index level using `earliest=-1h`, which leverages Splunk’s time-based index pruning to scan only events from the last hour, drastically reducing the data volume processed before the `stats` command aggregates counts per host. On the Splunk Core Certified Power User SPLK-1003 exam, this question tests your understanding of efficient time filtering—a key concept for optimizing search performance in large environments. A common trap is using `WHERE _time` or `earliest` after a pipe, which forces Splunk to retrieve all events first, wasting resources. Remember: always push time filters as early as possible in the search pipeline. Memory tip: “Time first, stats last” ensures your filter runs at the index level, not after data retrieval.
SPLK-1003 Advanced Searching and Statistics Practice Question
This SPLK-1003 practice question tests your understanding of advanced searching and statistics. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
To count events by host for the last hour, which search is most efficient?
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
index=* earliest=-1h | stats count by host
Option A is correct because it uses `index=*` to search all indexes and `earliest=-1h` to restrict the search to the last hour at the index level, which is the most efficient way to filter time. The `stats count by host` then aggregates counts per host without needing to process events outside the time range. This approach leverages Splunk's time-based index pruning, minimizing data scanned.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✓
index=* earliest=-1h | stats count by host
Why this is correct
Applies time range early, minimizing data scanned.
Related concept
Read the scenario before looking for a memorised answer.
✗
index=* | stats count by host | where _time > relative_time(now(), "-1h")
Why it's wrong here
Stats processes all events before filtering by time.
✗
search index=* | head 1000 | stats count by host
Why it's wrong here
Only uses first 1000 events, not representative of the last hour.
✗
sourcetype=access_combined | timechart count by host
Why it's wrong here
Timechart creates a time series, which is unnecessary and uses more resources.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Splunk often tests the misconception that you can filter time after aggregation (as in Option B) or that limiting results with `head` is equivalent to time-based filtering, when in fact time filters must be applied at search time via `earliest`/`latest` for efficiency and correctness.
Detailed technical explanation
How to think about this question
Under the hood, Splunk uses a time-based index structure where each bucket is organized by time range; `earliest=-1h` tells the search head to only scan buckets that overlap with the last hour, drastically reducing I/O. The `stats` command operates on the event stream and can use memory-efficient aggregation, whereas `timechart` would create additional time-series overhead. In real-world scenarios with high-volume data (e.g., 10 TB/day), using `earliest` is critical to avoid scanning terabytes of irrelevant data.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the SPLK-1003 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Advanced Searching and Statistics — This question tests Advanced Searching and Statistics — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: index=* earliest=-1h | stats count by host — Option A is correct because it uses `index=*` to search all indexes and `earliest=-1h` to restrict the search to the last hour at the index level, which is the most efficient way to filter time. The `stats count by host` then aggregates counts per host without needing to process events outside the time range. This approach leverages Splunk's time-based index pruning, minimizing data scanned.
What should I do if I get this SPLK-1003 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Question Discussion
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