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COF-C03 Practice Question: Performance Optimization, Querying, and Transformation

Which technique is recommended to improve the performance of a query that must frequently filter data based on values within a VARIANT column containing JSON data?

⚠ Common exam trap

Candidates often suggest using more compute resources or caching, failing to realize that materializing keys into relational columns is the best practice for optimizing JSON query performance.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

Materialize frequently used JSON keys into separate relational columns.

Querying semi-structured data is efficient in Snowflake, but performance can be further enhanced by creating 'functional' elements. Since Snowflake micro-partitions store VARIANT data in a columnar fashion, extracting common fields into their own relational columns allows the engine to use standard pruning and statistics more effectively.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✗

    Convert the JSON into a single large string and use LIKE operators.

    Why it's wrong here

    Using LIKE operators on large strings is extremely inefficient because it usually requires a full table scan and prevents the use of micro-partition metadata. This approach bypasses Snowflake's optimizations for semi-structured data and will lead to significantly slower query performance and higher costs.

  • ✗

    Create a separate table for every key-value pair in the JSON.

    Why it's wrong here

    This approach, known as over-normalization, creates massive complexity in the data model and requires numerous joins for even simple queries. It negates the flexibility of the VARIANT type and is difficult to maintain as the schema of the source JSON data evolves over time.

  • ✓

    Materialize frequently used JSON keys into separate relational columns.

    Why this is correct

    By extracting common JSON keys into standard relational columns (either during ingestion or via a view/dynamic table), Snowflake can better utilize micro-partition pruning. This allows the query engine to skip data more effectively, resulting in faster performance for filters on those specific fields.

  • ✗

    Disable the use of the result cache for all JSON-based queries.

    Why it's wrong here

    Disabling the result cache would only hurt performance by forcing Snowflake to re-calculate every query from scratch. The result cache is actually very beneficial for repetitive queries on JSON data, and disabling it does nothing to improve the underlying execution speed of the scan.

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JA

Written and reviewed by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

Last reviewed September 2026 · checked against the official Snowflake exam blueprint

This COF-C03 practice question is part of Courseiva's free Snowflake certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the COF-C03 exam.