ARA-C01 Performance Optimization Practice Question
While reviewing a Query Profile, an architect notices that a 'Join' operator is consuming 90% of the total execution time, and one specific node in the warehouse is processing significantly more rows than others. What is the most likely cause and the best resolution?
⚠ Common exam trap
Candidates often blame the warehouse size for slow joins, overlooking the symptom of uneven row processing which is a classic indicator of data skew rather than insufficient compute.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The query is experiencing data skew; investigate the join key distribution.
Data skew occurs when the data is not evenly distributed across the join key. This causes one node in the warehouse to perform the majority of the work while others remain idle. To resolve this, the architect should consider using a different join key or applying a 'skew hint' if supported, or pre-aggregating the skewed data.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The warehouse size is too small; increase it to a larger T-shirt size.
Why it's wrong here
Increasing the warehouse size will provide more nodes, but if the data is skewed, the new nodes will also be underutilized while the node holding the skewed key remains the bottleneck. Scaling up may hide the symptom by providing more power to the bottlenecked node, but it doesn't fix the underlying distribution issue.
- ✓
The query is experiencing data skew; investigate the join key distribution.
Why this is correct
The symptom of one node processing significantly more rows than others is a classic indicator of data skew. The architect should analyze the distribution of values in the join column. If a single value (like NULL or a default ID) appears in millions of rows, it will concentrate processing on a single node.
- ✗
The Result Cache is cold; run the query again to populate the cache.
Why it's wrong here
The Result Cache stores the final output of a query, not the intermediate state of a join operator. A cold cache would cause the entire query to be re-run, but it would not cause the specific imbalance between nodes within a join operator that is described in the scenario.
- ✗
The table is not clustered; apply a clustering key to the join column.
Why it's wrong here
Clustering improves pruning (skipping data), but it does not necessarily resolve distribution issues during a join. Joins involve shuffling data across the warehouse nodes based on a hash of the join key. Even if a table is clustered, a skewed key will still result in an uneven hash distribution across nodes.
Visual reference
About these practice questions
Courseiva writes every ARA-C01 question from scratch — 209 in total, each with an explanation and a wrong-answer breakdown. None are copied from real exams or dumps. Learn why practice questions differ from exam dumps →
JA
Written and reviewed by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
Last reviewed September 2026 · checked against the official Snowflake exam blueprint
This ARA-C01 practice question is part of Courseiva's free Snowflake certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the ARA-C01 exam.