EX200 Create and configure file systems Practice Question
Exhibit
Refer to the exhibit. Output of 'pvscan' and 'vgdisplay': PV /dev/sda2 VG vg00 lvm2 [19.99 GiB / 0 free] PV /dev/sdb1 VG vg00 lvm2 [19.99 GiB / 19.99 GiB free] Total: 2 [39.98 GiB] / in use: 2 [39.98 GiB] / in no VG: 0 [0 ] --- Volume group --- VG Name vg00 System ID Format lvm2 Metadata Areas 2 Metadata Sequence No 6 VG Access read/write VG Status resizable MAX LV 0 Cur LV 3 Open LV 3 Max PV 0 Cur PV 2 Act PV 2 VG Size 39.98 GiB PE Size 4.00 MiB Total PE 10235 Alloc PE / Size 5120 / 20.00 GiB Free PE / Size 5115 / 19.98 GiB VG UUID abcd1234
Based on the exhibit, how much free space is available in the volume group vg00?
⚠ Common exam trap
Red Hat often tests the distinction between raw PV size and usable VG space, trapping candidates who assume the PV size equals the VG free space without accounting for PE size and rounding.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
19.98 GiB
The VG free space is calculated from the total number of Physical Extents (PEs) and the PE size. The output shows 5115 PEs and a PE size of 4.00 MiB, so total free space = 5115 × 4 MiB = 20460 MiB = 19.98 GiB (since 20460 ÷ 1024 = 19.98046875). No Logical Volumes are allocated, so all PEs are free. Option B (10235 MiB) is exactly half of 20470 MiB, a common miscalculation. Option C (20.00 GiB) is the raw PV size, ignoring the PE overhead. Option D (19.99 GiB) is a rounding error. Option E (5115 MiB) confuses the PE count with the free space in MiB.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
19.98 GiB
Why this is correct
In vgdisplay, the Free PE count is 5115 and the PE size is 4.00 MiB, so the unallocated capacity equals 5115 × 4 = 20,460 MiB. Converting MiB to GiB by dividing by 1024 yields 19.98 GiB, which is the available free space. This is the exact value that vgdisplay reports as the remaining space in the volume group.
- ✗
10235 MiB
Why it's wrong here
The number 10235 MiB incorrectly treats the Total PE count as if it were a size in MiB. The total PE count is a count of extents, not megabytes; with a 4 MiB PE size, the actual total capacity is 10235 × 4 = 40,940 MiB. Free space is 5115 PEs, not 10,235.
- ✗
20.00 GiB
Why it's wrong here
The 20.00 GiB figure is the allocated space, not the free space. If 5120 PEs are allocated at 4 MiB each, that is 5120 × 4 = 20,480 MiB, which equals exactly 20.00 GiB. The question asks for free space, which is the remaining 5115 PEs, about 19.98 GiB.
- ✗
19.99 GiB
Why it's wrong here
The value 19.99 GiB reflects the capacity of a single physical volume in the group, typically shown in pvdisplay, not the volume group's free space. Each PV may be sized at 19.99 GiB, but free space is determined by the group's Free PE count (5115) multiplied by the PE size (4 MiB), giving 19.98 GiB. Confusing per-PV capacity with aggregate free capacity leads to this incorrect answer.
- ✗
5115 MiB
Why it's wrong here
(5115 MiB) mistakenly uses the number of Physical Extents (PEs) as the free space in MiB. The actual free space is 5115 PEs × 4 MiB/PE = 20460 MiB = 19.98 GiB, not 5115 MiB.
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